Given the sequence:
6, 10, 14, 18,...
We will find the 75th term
The given sequence is an arithmetic sequence
Because there is a constant common differnce
d = 18 - 14 = 14 - 10 = 10 - 6 = 4
The first term = a = 6
The general formula of the arithmetic sequence is as follows:

Where: n is the nth term
To find the 75th term, substitute with n = 75 and a = 6, d = 4

So, the answer will be the 75th term = 302
Answer:
I got 12√ 2
PLZ CORRECT ME IF I AM WRONG PLZ AND THXS YOU
Step-by-step explanation:
Answer:
(1,-1)
Step-by-step explanation:
X goes up +1 and Y goes down -1

you're given both, plug them in
Answer: Mean = 4.8 and variance = 5.16
Step-by-step explanation:
Since we have given
Let X be the number of storms occur in next year
Y= 1 if the next year is good.
Y=2 if the next year is bad.
Mean for good year = 3
probability for good year = 0.4
Mean for bad year = 5
probability for bad year = 0.6
So, Expected value would be
![E[x]=\sum xp(x)\\\\=3\times 0.4+5\times 0.6\\\\=1.2+3\\=4.2](https://tex.z-dn.net/?f=E%5Bx%5D%3D%5Csum%20xp%28x%29%5C%5C%5C%5C%3D3%5Ctimes%200.4%2B5%5Ctimes%200.6%5C%5C%5C%5C%3D1.2%2B3%5C%5C%3D4.2)
Variance of the number of storms that will occur.
![Var[x]=E[x^2]-(E[x])^2](https://tex.z-dn.net/?f=Var%5Bx%5D%3DE%5Bx%5E2%5D-%28E%5Bx%5D%29%5E2)
![E[x^2]=E[x^2|Y=1].P(Y=1)+E[x^2|Y=2].P(Y=2)\\\\=(3+9)\times 0.4+(5+25)\times 0.6\\\\=12\times 0.4+30\times 0.6\\\\=4.8+18\\\\=22.8](https://tex.z-dn.net/?f=E%5Bx%5E2%5D%3DE%5Bx%5E2%7CY%3D1%5D.P%28Y%3D1%29%2BE%5Bx%5E2%7CY%3D2%5D.P%28Y%3D2%29%5C%5C%5C%5C%3D%283%2B9%29%5Ctimes%200.4%2B%285%2B25%29%5Ctimes%200.6%5C%5C%5C%5C%3D12%5Ctimes%200.4%2B30%5Ctimes%200.6%5C%5C%5C%5C%3D4.8%2B18%5C%5C%5C%5C%3D22.8)
So, Variance would be

Hence, Mean = 4.8 and variance = 5.16