Let r, g and b represent red, green and blue.
r+g+b = 74
r=g-1
b=r+g
Again, r+g+b = 74. Let's substitutte r+g for b: r+g+(r+g) = 74.
Next, let's eliminate r. Use r=g-1. Then g-1 + g + g-1 + g = 74
Combining the g terms, 4g - 2 = 74 => 4g = 76 => g = 19
Recall that r=g-1
and
b=r+g
Find r. If r=g-1, and g=19, then r = 19-1=18
Find b: b = r+g = 18+19=37
So there are 37 blue candies, 18 red candies and 19 green candies.
Check: 37+18+19=74 ??? Yes.
Answer:
6cm
Step-by-step explanation:
= 6
Answer: The numbers are 10 and 23
Step-by-step explanation:
Let the smaller number be x
And the larger number be y
Ist sentence;
1. The sum of two numbers is 33.
X + y= 33 .........eqn 1
2. second sentence
the larger number is 3 more than two times the smaller number.
Y = 3 +2x
Put y into eqn 1
X+ 3 +2x = 33
3x= 33- 3
3x= 30
X = 30/3
X= 10 and y= 3+ 2x
Y= 3+ 2(10)
Y = 3+ 20
Y= 23
Therefore the two numbers are 10 and 23
Answer:
1entire group
2part
3particular condition
4random and large enough
5range of the middle half
6
7
8
9 average
10middle of a sorted list
11which appears more often
12 the lowest and highest
13mirrors
14
15
Step-by-step explanation:
Im not sure about the rest
