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4 years ago

Which property may be necessary during the process of solving equations with parentheses? Select all that apply

Mathematics

2 answers:

Alinara [238K]4 years ago

4 0

Reflexive, multiplication and distributive. Hope that helps! :)

Olenka [21]4 years ago

4 0

Answer:

addition property of equality

multiplication property of equality

distributive property.

Step-by-step explanation:

We use addition property of equality , multiplication property of equality and distributive property.

We will not use reflexive property which is x = x.

Let me show you an example.

solve the following equation:

2(x - 1) = 8

Use distributive property a(b - c) = a.b - a.c

2x - 2 = 8

Add 2 on both sides. Addition property of equality.

2x -2 + 2 = 8 + 2

2x = 10

Now multiply both sides by the reciprocal of 2, which is 1 over 2, we get

x = 5

Therefore, the answer is " addition property of equality , multiplication property of equality and distributive property."

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To prove that the triangles are similar by the SSS similarity theorem, which other sides or angles should be used?]

Margarita [4]

Answer: $\overline{MN}$ and $\overline{QR}$

Step-by-step explanation:

Given: In ΔMNO and ΔQRS

$\frac{SQ}{OM}=\frac{SR}{ON}=4$

To prove that the triangles are similar by the SSS similarity theorem [corresponding sides of similar triangles are proportional], there must be the third pair of corresponding sides,

That must be $\overline{MN}$ and $\overline{QR}$

such that $\frac{QR}{MN}=4$

3 0

3 years ago

Read 2 more answers

Help please? 10 points. Correctly

Romashka [77]

From the Figure :

Point A is (-3 , -3)

Point B is (6 , 6)

We know that, The Mid Point of Two Points (x₁ , y₁) and (x₂ , y₂) is given by :

$\mathsf{\implies [(\frac{x_1 + x_2}{2})\;,\;(\frac{y_1 + y_2}{2})]}$

$\mathsf{\implies Midpoint\;of\;Line\;AB\;is\;[(\frac{-3 + 6}{2})\;,\;(\frac{-3 + 6}{2})]}$

$\mathsf{\implies Midpoint\;of\;Line\;AB\;is\;[(\frac{3}{2})\;,\;(\frac{3}{2})]}$

$\mathsf{\implies Midpoint\;of\;Line\;AB\;is\;(1.5,1.5)}$

4 0

3 years ago

Directions for questions 4 & 5: We selected a random sample of 100 StatCrunchU students, 67 females and 33 males, and analyz

GaryK [48]

Answer:

The 95% confidence interval for the difference between means is (-2164.21, -299.13).

The lower limit on the confidence interval is -$2164.21.

The upper limit on the confidence interval is -$299.13.

Step-by-step explanation:

The sample data is:

Gender Mean Std. dev. n

Female 2577.75 1916.29 67

Male 3809.42 2379.47 33

We have to calculate a 95% confidence interval for the difference between means, with a T-model.

The sample 1, of size n1=67 has a mean of 2577.75 and a standard deviation of 1916.29.

The sample 2, of size n2=33 has a mean of 3809.42 and a standard deviation of 2379.47.

The difference between sample means is Md=-1231.67.

$M_d=M_1-M_2=2577.75-3809.42=-1231.67$

The estimated standard error of the difference between means is computed using the formula:

$s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{1916.29^2}{67}+\dfrac{2379.47^2}{33}}\\\\\\s_{M_d}=\sqrt{54808.468+171572.045}=\sqrt{226380.513}=475.795$