9514 1404 393
Answer:
y = 3x -8
Step-by-step explanation:
We assume you want the tangent to the parabola y = x² -3x +1 at the given point. The slope is found using the derivative of the function at that point.
y' = 2x -3
At x=3, the slope is ...
y' = 2(3) -3 = 3
The equation of the line through point (3, 1) with a slope of 3 is ...
y -1 = 3(x -3) . . . . use the point-slope form of the equation for a line
y = 3x -9 +1 . . . . . eliminate parentheses, add 1
y = 3x -8
Answer:
168.43524
Step-by-step explanation:
A=ah+bh+ch+1
2﹣a4+2(ab)2+2(ac)2﹣b4+2(bc)2﹣c4=7·6+7·6+7·6+1
2·﹣74+2·(7·7)2+2·(7·7)2﹣74+2·(7·7)2﹣74≈168.43524
Answer:
x = 0.5
Step-by-step explanation:
2(2x-1)=3
2(2x)+1=3
-1 -1
2(2x)=2 2x2=4
4x=2
4÷4 Cancels out the 4 in X
2÷4=0.5
Therefore
x = 0.5