3 years ago

How many moles are in 3.01 c 10^24 atoms of sodium chloride

Chemistry

1 answer:

Mademuasel [1]3 years ago

7 0

Answer:

number of moles = 5 moles

Explanation:

atomic mass of sodium chloride = 23+35.5 = 60.5 g

number of moles = (number of molecules)/(Avagadro number)

= $\frac{3.01\times 10^{24}}{6.023\times 10^{23}}$

=5 moles.

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A second-order reaction has a rate constant of 1.25 M-1 s-1. If the initial reactant concentration is 1.0 M (a) determine the ha

Ne4ueva [31]

Answer:

(a) 0.8 s

(b) t = 7.2 s

Explanation:

(a) Half life expression for second order kinetic is:

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Where,

$[A_o]$ is the initial concentration = 1.0 M

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So,

$t_{1/2}=\frac{1}{1.25\times 1.0}$

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(b) Integrated rate law for second order kinetic is:

$\frac{1}{[A_t]} = \frac{1}{[A]_0}+kt$

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So,

$\frac{1}{0.1} = \frac{1}{1.0}+1.25t$

t = 7.2 s

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stealth61 [152]

Answer:

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Explanation:

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