Answer:
The mass of water 
= 39.18 gm
Explanation:
Mass of iron 
= 32.5 gm
Initial temperature of iron 
= 22.4°c = 295.4 K
Specific heat of iron 
= 0.448 
Mass of water =
Specific heat of water 
Initial temperature of water 
= 336 K
Final temperature after equilibrium 
= 59.7°c = 332.7 K
When iron rod is submerged into water then
Heat lost by water = Heat gain by iron rod
( - ) = ( - )
Put all the values in above formula we get
× 4.2 × ( 336 - 332.7 ) = 32.5 × 0.448 × ( 332.7 - 295.4 )
= 39.18 gm
Therefore the mass of water = 39.18 gm
Answer:
The answer to your question is:
a) 31.75 cm
b) 0.475 miles
c) 2.44 yards
d) 11496.04 inches
Explanation:
Convert
a) 12.5 in to cm
1 in ------------------- 2.54 cm
12.5 in ---------------- x
x = 12.5(2.54)/1 = 31.75/ = 31.75 cm
b) 2513 ft to miles
1 mile -------------- 5280 ft
x miles ------------ 2513 ft
x = 2513(1)/5280 = 0.475 miles
c) 2.23 m to yards
1 m ------------- 1,094 yards
2.23 m ---------- x
x= 2.23x1.094/1 = 2.44 yards
d) 292 m to inches
1 m ---------------- 39.37 inches
292 m ------------- x
x = 292 x 39.37/1 = 11496.04 inches
Answer:
105 grams PbI₂
Explanation:
Pb(NO₃)₂ + 2KI => 2KNO₃ + PbI₂(s)
moles Pb(NO₃)₂ = 0.265L(1.2M) = 0.318 mole
moles KI = 0.293(1.55M) = 0.454 mole => Limiting Reactant
moles PbI₂ from mole KI in excess Pb(NO₃)₂ = 1/2(0.454 mole) = 0.227 mol PbI₂
grams PbI₂ = 0.227 mol PbI₂ x 461 g/mole = 104.68 g ≈ 105 g PbI₂(s)
We have to calculate formula mass of N₂O.
The answer is: 44
Relative formula mass is the sum of relative atomic mass of constituent atoms in a formula unit of any compound. Relative formula mass is represented as same symbol of relative molecular mass.
To calculate relative formula mass we need to know number of each atom in the formula and then adding atomic masses of all the atoms.
In N₂O, number of N-atom present is equal to 2 and number of O-atom is equal to 1.
Atomic mass of N-atom is 14 and atomic mass of O-atom is 16.
So, formula mass of N₂O is (2 X 14)+16 = 44.
