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kolezko [41]
4 years ago
8

Calculate the volume of oxygen required to burn 12.00 l of ethane gas, c2h6, to produce carbon dioxide and water, if the volumes

of c2h6 and o2 are measured under the same conditions of temperature and pressure
Chemistry
1 answer:
kirza4 [7]4 years ago
8 0
The  volume of   oxygen required  to  burn  12.00 L  ethane is calculated  as  follows

find the moles  of C2H6  used

At  STP  1 mole  is  always =  22.4 L, what about  12.00 L

= ( 12.00L  x 1 moles)  22.4 L = 0.536  moles

write the   reacting equation

2C2H6+  7O2 = 4CO2  + 6H2O
by  use  of mole  ratio  between  C2H6 :O2   which is 2:7  the  moles  of O2 

= 0.536  x7/2=  1.876  moles

again  at  STP  1mole =  22.4 L  what  about 1.876 moles

=    22.4 L x 1.876  moles/ 1 mole =  42.02 L


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Borax bead test

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Explanation:

The message of the book is that perseverance is necessary for success. If we focus on our goals and learn from others, we will be rewarded in the end.

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The parcial pressure of N₂ in the mixture is 1.24 atm.

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The pressure exerted by a particular gas in a mixture is known as its partial pressure. So, Dalton's law states that the total pressure of a gas mixture is equal to the sum of the pressures that each gas would exert if it were alone:

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This relationship is due to the assumption that there are no attractive forces between the gases.

In this case:

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You know:

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Replacing:

1.943 atm= 0.137 atm + 0.566 atm + PN₂

Solving:

1.943 atm= 0.703 atm + PN₂

1.943 atm - 0.703 atm= PN₂

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