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-Dominant- [34]
3 years ago
11

A molecular biologist measures the mass of cofactor a in an average yeast cell. the mass is 74.06 pg . what is the total mass in

micrograms of cofactor a in a yeast colony containing 105 cells
Chemistry
1 answer:
Brums [2.3K]3 years ago
7 0
We know that one cell of yeast is 74.06 pg. To know the total mass of 105 cells, we will simply use cross multiplication as follows:
total mass = (105 x 74.06) / 1 = 7773.15 pg.

Now, we need to change pg to micro-grams.
From the standard units conversions, we know that:
1 pico is equivalent to <span>0.000001 micro.
</span>Therefore,
total mass = (7773.15 x 0.000001) / 1 = 0.00777315 micro-grams
                 = 7.77315 x 10^-3 micro-grams

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What coefficients should be added in order to make this a balanced equation?
Vanyuwa [196]

Answer:

Hello

Coefficients are 1,3,2,1

Explanation

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4 years ago
The formation of a plaque and halitosis can be avoided by brushing and flossing at least :
Jet001 [13]

Answer:

at least 3 times a day

Explanation:

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3 years ago
1.86 g of ethanol reacts with 10.0 g of oxygen. What is the total volume of gas present (in L) after the reaction is complete, a
vladimir1956 [14]

Answer:

See explanation

Explanation:

The equation of the reaction is;

C 2 H 6 O(l)  +  3 O 2 (g)  → 2 CO 2 ( g )  +  3 H 2 O(l )

Next we have to determine the limiting reactant, this reactant gives the least number of moles of product.

Number of moles of C 2 H 6 O = mass/molar mass = 1.86g/ 46.07 g/mol = 0.04 mols

From the equation;

1 mol of ethanol yields 2 mols of CO2

0.04 moles of ethanol yields 0.04 * 2/1 = 0.08 mols of CO2

For water;

1 mol of ethanol yields 3 mols of water

0.04 moles of ethanol yields 3 * 0.04/1 = 0.12 mols of water

Also;

Number of moles of oxygen= 10g/32g/mol = 0.31 moles

3mols of O2 yields 2 moles of CO2

0.31 moles of O2 yields 0.31 * 2/3 = 0.21 moles of CO2

For water;

3 moles of O2 yields 3 moles of water

0.31 moles of O2 yields 0.31 * 3/3 = 0.31 moles of water

Hence ethanol is the limiting reactant.

From  PV=nRT

Volume of CO2 is;

V = nRT/P

V = 0.08 * 0.082 *298/1 = 1.95 L

Volume of water;

V = nRT/P

V= 0.12 * 0.082 * 298/1

V= 2.93 L

Total volume of gases after reaction = 1.95 L + 2.93 L = 4.88 L

6 0
3 years ago
What is the edge length of a face-centered cubic unit cell that is made of of atoms, each with a radius of 154 pm
gladu [14]

Answer:

The edge length of a face-centered cubic unit cell is 435.6 pm.

Explanation:

In a face-centered cubic unit cell, each of the eight corners is occupied by one atom and each of the six faces is occupied by a single atom.

Hence, the number of atoms in an FCC unit cell is:

8*\frac{1}{8} + 6*\frac{1}{2} = 4 atoms

In a face-centered cubic unit cell, to find the edge length we need to use Pythagorean Theorem:

a^{2} + a^{2} = (4R)^{2}     (1)

Where:

a: is the edge length

R: is the radius of each atom = 154 pm      

By solving equation (1) for "a" we have:

a = 2R\sqrt{2} = 2*154 pm*\sqrt{2} = 435.6 pm    

Therefore, the edge length of a face-centered cubic unit cell is 435.6 pm.   

I hope it helps you!

7 0
4 years ago
Nitrogen gas is stored at 200 kPa and 100 K in a rigid tank with a volume of 0.5 m3. If the temperature of the gas is increased
olasank [31]

Answer:

The final temperature is 800KPa

Explanation:

The following were obtained from the question:

P1 = 200 kPa

T1 = 100 K

T2 = 400 K

P2 =?

Since the tank is rigid, the volume of the tank is constant.

Using P1/T1 = P2/T2, we can obtain the new pressure as illustrated below:

200/100 = P2 /400

Cross multiply to express in linear form:

100 x P2 = 200 x 400

Divide both side by 100

P2 = (200 x 400) /100

P2 = 800KPa

The final temperature is 800KPa

3 0
4 years ago
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