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Dmitry [639]
3 years ago
13

Which of the following is true?

Biology
1 answer:
gayaneshka [121]3 years ago
5 0

The answer is B.

A. False. Heterotrophs need to consume other organisms to make energy.

C. False. Thermophiles (notice the prefix 'thermo') are organisms that thrive at higher than normal temperatures.

D. False. Autotrophs make their own energy. They don't consume it from other sources.

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2. Dominant trait: cleft chin (C) Mother’s gametes: Cc
andre [41]

.2. Offspring Genotypes will be Cc or cc.

     Offspring phenotypes : Cleft chin or no cleft chin.

    % chance child will have cleft chin: 50%

3.  % chance child will have arched feet: 25%

4.  % chance child will have blonde hair:  50%

5.  % chance child will have normal vision: 25%

 

Explanation:

CASE 1 :

 Dominant trait: cleft chin (C)

    Recessive trait: lacks cleft chin (c)

    Father’s gametes: cc

    Mother’s gametes: Cc

There are two possible combination of Gametes ,

C fom mother and  c from father= Cc

c from mother and c from father = cc

Gametes of Cc Parents=  \frac{1}{2}C + \frac{1}{2} c........(i)

Gametes of cc parents =<u> </u>\frac{1}{2}c + \frac{1}{2}c .........(ii)

Combining (i) and (ii) we get,

\frac{1}{2}  Cc + \frac{1}{2} cc                              

There fore offspring Genotypes will be Cc or cc

Offspring phenotypes :

Genotype Cc then phenotype= Cleft chin

Genotype cc then phenotype = Lacks cleft chin.

percentage chance child will have cleft chin  =\frac{0.5}{1} ×100

Therefore the chance is 50%.

CASE 2 :

Dominant trait: flat feet (A)

Recessive trait: arched feet (a)

Mother’s gametes: Heterozygous (Aa)

Father’s gametes: Heterozygous   (Aa)

There are four possible combination of genotypes are =AA , Aa, Aa and aa

i.e. A from mother, A from father= AA

     A from mother, a from father =Aa

     a from mother, A from Father = Aa

     a from mother, a from father = aa

Gametes of Aa parent =\frac{1}{2} A + \frac{1}{2} a

Gametes of other Aa parent = \frac{1}{2} A + \frac{1}{2} a

                                       <u>..................................................................................</u>

                                              \frac{1}{4} AA + \frac{1}{4} Aa

                                                                           +  \frac{1}{4} Aa +\frac{1}{4} aa

                                   <u>..........................................................................................</u>

                                <u>\frac{1}{4}AA + \frac{1}{2}Aa +\frac{1}{4} aa</u>

Offspring Genotypes will be: AA or Aa or aa

Offsprings phenotype will be:

Genotype AA then phenotype will be Flat feet

Genotype Aa then phenotype will be flat feet

Genotype aa then Phenotype will be arched feet.

Percentage chance child will have arched feet = \frac{0.25}{1} × 100 = 25%

CASE 3:

Dominant trait: Brown hair (B)

Recessive trait: Blonde hair (b)

Mother’s gametes: Homozygous recessive  (bb)

Father’s gametes: Heterozygous  (Bb)

This case is very similar to the case 1 as one parent is homozygous recessive and other parent is heterozygous.

Resulting in  half  Bb and halve bb combination.

Genotypes will be Bb or bb

Phenotypes will be :

Genotype Bb then phenotype Brown hair

Phenotype bb then Phenotype bb.

% chance child will have blonde hair: 50%

CASE 4:

Dominant trait: farsightedness (F)

Recessive trait: normal vision (f)

Mother’s gametes: Heterozygous  (Ff)

Father’s gametes: Heterozygous  (Ff)

This Case is similar to case 2

it will result in one-fourth FF , half Ff and one-fouth ff combination.

Therefore Genotypes will be: FF, Ff and ff

Phenotypes:

Genotype FF  then phenotype farsightedness

Genotype Ff then phenotype  farsightedness

Genotype ff then phenotype normal vision.

% chance child will have normal vision: 25%

 

3 0
3 years ago
What would acid would be use to remove bricks mortar
Marina CMI [18]
Hihi!

The answer would have to be <span>muriatic </span>acid! This acid<span> needs to be actually diluted before you can </span>use<span> it or you </span>can<span> permanently damage the </span>brick, that's how strong it is!<span> 

I hope I helped!
-Loliarual</span>
4 0
3 years ago
Describe the technique used to care for instrumentation and supplies that have been exposed to the inside of the intestinal trac
Kitty [74]

Answer:

The instruments that is being used to care for the instrumentation and supplies that have been exposed to the inside of intestinal tract are kept aside from the other sterile instruments.

The instruments are kept aside to protect the other instruments from being contaminated by it.

The instruments needs to be sterile as it cannot be replaced again and again for every technique that is being carried out in patients.

So, the instrument that is used once are kept separated.

6 0
2 years ago
What is one defining feature of a prokaryotic cell?
Vanyuwa [196]

Answer:

the answer is D

Explanation:

8 0
2 years ago
Read 2 more answers
Which of the following is not an example of ectotherms?
lorasvet [3.4K]
A.human
c.turtles
because ectotherm also known as cold blooded ,which is any animal whose regulation of body temperature depends on external sources
7 0
3 years ago
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