The height of the triangle is 21.35 cm
Explanation:
It is given that the area of the triangle = ![1140 cm^2](https://tex.z-dn.net/?f=1140%20cm%5E2)
Let h be the height of the triangle.
It is also given that the base is 5 times the height.
Thus, ![b=5h](https://tex.z-dn.net/?f=b%3D5h)
Now, substituting these values in the formula,
![A=\frac{1}{2} bh](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B2%7D%20bh)
![1140=\frac{1}{2} \times 5h \times h](https://tex.z-dn.net/?f=1140%3D%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%205h%20%5Ctimes%20h)
![1140=\frac{5h^2}{2}](https://tex.z-dn.net/?f=1140%3D%5Cfrac%7B5h%5E2%7D%7B2%7D)
Multiplying both sides by 2,
![2280=5h^2](https://tex.z-dn.net/?f=2280%3D5h%5E2)
Dividing both sides by 5,
![456=h^2](https://tex.z-dn.net/?f=456%3Dh%5E2)
Taking square root on both sides, we get,
![h=21.35](https://tex.z-dn.net/?f=h%3D21.35)
Thus, the height of the triangle is