2 years ago

Express 125 = 5x as a logarithmic equation.

1 answer:

3 0

Answer: x log[5] = log[125]

Explanation:

The original expression is 125 = 5^x

To express that as a logarithmic equation take logarithms on both sides:

log [125] = [log 5^x]

By the properties of the logartims of powers that is:

log [125] = x log[5]

And that is the equation required.

If you want to solve it, you can do 125 = 5^2, and apply the same property (logarithm of a power) to the left side, yielding to:

log [5^2 ]= x log[5]

=> 2 log[5] = x log[5]

=> 2 = x

You might be interested in

What is the perimeter of a rectangle

natta225 [31]

p=2(l+w)

p=2(6+8)

p=2(14)

p=28

7 0

3 years ago

Read 2 more answers

Please give a detailed explanation

sweet [91]

$\displaystyle \large \boldsymbol{} (7 \sqrt[5]{6x-10}) ^2 +\backslash\!\!\!8=\frac{49}{x^{-\tfrac{2}{5} }} +\backslash\!\!\!8 \\\\\\ 49\!\!\!\! \diagup \sqrt[5]{(6x-10)^2} = 49\!\!\!\! \diagup \cdot \sqrt[5]{x^2} \ \ ; \\\\\\ (6x-10)^2=x^2 \\\\ (6x-x-10)(6x+x-10) =0 \Rightarrow x_1=2 \ ; \ x_2=\frac{10}{7 }$