a rectangle 24 meters long has the same area as a square with 12 meter sides. what are the dimensions of the rectangle?

Joy wants to save $50 to buy a pair of roller blades. He plans to save $2 in the first month, $4 in the second month, $6 in the

Alika [10]

Answer:

it will take joy 7 months to buy a pair of roller blades.

Step-by-step explanation:

50

2,4,6,8,10,12,14

i think this is the right answer as you did not put the whole question

so i assume it keeps on going up in 2s.

hope this helps

3 0

2 years ago

5 x the sum of a number and 2 is less than the number x 8. Find the number

telo118 [61]

The solution to inequality is not a number but an interval.

$5(x+2) < 8x \\5x+10 < 8x \\10 < 3x \\10/3 < x \\x > 10/3\Longrightarrow x\in(10/3, +\infty)$

Hope this helps.

4 0

4 years ago

Please solve this for 15 points

maw [93]

Answer:

A) (2,8) and ( 3,12)

B) porportional

thats all i know sorry

Step-by-step explanation:

brainliest plz i need it. thx

7 0

3 years ago

Solve the system of equations

Solnce55 [7]

Hey, there!!

Given that:

y = 3x.........(i)

$y = {x}^{2} + 3x - 16.......(ii)$

Putting the value of y in equation (ii)

${3x}^{} = {x}^{2} + 3x - 16$

${x }^{2} - 16$ =0

$( {x)}^{2} - {4}^{2} = 0$

$(x + 4)(x - 4) = 0$

Therefore,

Either Or

(x+4)=0 (x-4)=0

x= -4 x= 4

so, x= (+ -)4

And if you wanna get value of y, just keep value of x in equation (i).

y= 3x

y= (3×4) or (3×-4)

y= 12 or -12

{As it is the quadratic equation it has two values. }

Hope it helps....

5 0

3 years ago

The number of chocolate chips in an 18-ounce bag of chocolate chip cookies is approximately normally distributed with a mean of

Svetach [21]

Answer:

(a) P(1000 < X < 1500) = 0.0256

(b) P(X < 1025) = 0.0392

(c) P(X > 1200) = 0.6554

(d) Percentile rank of a bag that contains 1425 chocolate chips = 90.98%

Step-by-step explanation:

We are given that the number of chocolate chips in an 18-ounce bag of chocolate chip cookies is approximately normally distributed with a mean of 1252 chips and standard deviation 129 chips.

Firstly, Let X = number of chocolate chips in a bag

The z score probability distribution for is given by;

Z = $\frac{ X - \mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean = 1252 chips

$\sigma$ = standard deviation = 129 chips

(a) Probability that a randomly selected bag contains between 1000 and 1500 chocolate chips, inclusive is given by = P(1000 $\leq$ X $\leq$ 1500) = P(X $\leq$ 1500) - P(X < 1000)

P(X $\leq$ 1500) = P( $\frac{ X - \mu}{\sigma}$ $\leq$ $\frac{1500-1252}{129}$ ) = P(Z $\leq$ 1.92) = 0.9726

P(X < 1000) = P( $\frac{ X - \mu}{\sigma}$ < $\frac{1000-1252}{129}$ ) = P(Z < -1.95) = 1 - P(Z $\leq$ 1.95)

= 1 - 0.9744 = 0.0256

Therefore, P(1000 $\leq$ X $\leq$ 1500) = 0.9726 - 0.0256 = 0.947

(b) Probability that a randomly selected bag contains fewer than 1025 chocolate chips is given by = P(X < 1025)

P(X < 1025) = P( $\frac{ X - \mu}{\sigma}$ < $\frac{1025-1252}{129}$ ) = P(Z < -1.76) = 1 - P(Z $\leq$ 1.76)

= 1 - 0.9608 = 0.0392

(c) Proportion of bags contains more than 1200 chocolate chips is given by = P(X > 1200)

P(X > 1025) = P( $\frac{ X - \mu}{\sigma}$ > $\frac{1200-1252}{129}$ ) = P(Z > -0.40) = P(Z < 0.40) = 0.6554

(d) Percentile rank of a bag that contains 1425 chocolate chips is given by;

Firstly we will calculate the z score of 1425 chocolate chips, i.e.;

Z = $\frac{1425-1252}{129}$ = 1.34

Now, we will check the area probability in z table which corresponds to this critical value of x;

The value which we get is 0.9098.

Therefore, 90.98% is the rank of bag that contains 1425 chocolate chips.

8 0

4 years ago