What is the solution too: R is between Q and S. If RS = 44.6 and SQ = 68.4 find QR
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The standard form of a line is in the form
A, B and C are integers, and A is positive. Let's start with multiplying the whole equation by 3 to get rid of denominators:
Subtract 3y from both sides:
Which of course is equivalent to
Which is the standard form, given the coefficients A=1, B=-3, C=6.
See the blue dot in the attached image.
First, find the x value on the coordinate plane. The x value is the first number in the point coordinates, so in this case, it is 4. Move to the right 4. (If it was negative, you would move to the left.)
Then, find the y value, which is the second number of the coordinates. In this case, it is -1, so move down 1. (If it was positive, you’d move up.)
Now, mark this point. This is (4, -1).
First, find the x value on the coordinate plane. The x value is the first number in the point coordinates, so in this case, it is 4. Move to the right 4. (If it was negative, you would move to the left.)
Then, find the y value, which is the second number of the coordinates. In this case, it is -1, so move down 1. (If it was positive, you’d move up.)
Now, mark this point. This is (4, -1).