Which of the diagrams below represents the statement “if it is a square then it is a quadrilateral
1 answer:
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X intercept: when Y = 0
Y intercept: when X = 0
Plug into equation
4x + 6(0) = 12
4x = 12, x = 3
Therefore x int = (3,0)
4(0) + 6y = 12
6y = 12, y = 2
Therefore y int = (0,2)
Plug those points then draw a line through them
Y intercept: when X = 0
Plug into equation
4x + 6(0) = 12
4x = 12, x = 3
Therefore x int = (3,0)
4(0) + 6y = 12
6y = 12, y = 2
Therefore y int = (0,2)
Plug those points then draw a line through them
Given a polynomial and a point
, we have that
We know that our cubic function is zero at -4, 0 and 5, which means that our polynomial is a multiple of
Since this is already a cubic polynomial (it's the product of 3 polynomials with degree one), we can only adjust a multiplicative factor: our function must be
To fix the correct value for a, we impose :
And so we must impose
So, the function we're looking for is