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Leni [432]
3 years ago
8

There are 13 teams of cheerleaders at a competition. The order of performance is determined at random. What is the probability t

hat your team performs first and your friend's tema is second?
Mathematics
1 answer:
PIT_PIT [208]3 years ago
3 0

probability of you performing first is 1/13

after your team performs there are 12 teams left, so chance of the other team performing next is 1/12


chance of both happening = 1/13 * 1/12 = 1/156

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2 r squared + 3s cubed minus r squared + 40 squared minus r squared if R equals -2 s equals -3 and T equals 5
Flura [38]

2r^2+3s^2-r^2+4t^2-r^2\\\\\text{simplify}\\\\(2r^2-r^2-r^2)+3s^2+4t^2=3s^2+4t^2\\\\s=-3;\ t=5\\\\3(-3)^2+4(5)^2=3(9)+4(25)=27+100=127

6 0
3 years ago
Write an equation for the nth term of the arithmetic sequence −15, −33, −51, −69, .... An equation for the nth term of the
stira [4]

Given:

The arithmetic sequence is −15, −33, −51, −69.

To find:

The nth term of the arithmetic sequence.

Solution:

We have,

−15, −33, −51, −69

Here,

First term: a = -15

Common difference is

d = -33-(-15)

d = -33+15

d = -18

Now, nth term  of an arithmetic sequence is

a_n=a+(n-1)d

Substitute a=-15 and d=-18.

a_n=-15+(n-1)(-18)

a_n=-15-18n+18

a_n=-18n+3

Therefore, the nth term of the given arithmetic sequence is a_n=-18n+3.

4 0
3 years ago
In this figure, what can be concluded about the distance from point B to CD?
maxonik [38]
It is the same distance from the point A to CD
4 0
3 years ago
Read 2 more answers
Please help me with these rotation problem.​
FrozenT [24]

Answer:

  see below

Step-by-step explanation:

In the attachment, the points are listed in the order given in the problem statement. (They are listed to the right of the "rotation matrix", with x-coordinates above y-coordinates.)

__

I really don't like to do repetitive calculations, so I try to use a graphing calculator or spreadsheet whenever possible. Angles are measured CCW.

As always, the rotation transformations are ...

  180° — (x, y) ⇒ (-x, -y)

  270° — (x, y) ⇒ (y, -x)

3 0
3 years ago
Indicate the equation of the given line in standard form. Show all your work for full credit. the line containing the median of
alukav5142 [94]

Answer:

* The equation of the median of the trapezoid is 10x + 6y = 39

Step-by-step explanation:

* Lets explain how to solve the problem

- The slope of the line whose end points are (x1 , y1) , (x2 , y2) is

  m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

- The mid point of the line whose end point are (x1 , y1) , (x2 , y2) is

  (\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})

- The standard form of the linear equation is Ax + BC = C, where

  A , B , C are integers and A , B ≠ 0

- The median of a trapezoid is a segment that joins the midpoints of

 the nonparallel sides

- It has two properties:

# It is parallel to both bases

# Its length equals half the sum of the base lengths

* Lets solve the problem

- The trapezoid has vertices R (-1 , 5) , S (! , 8) , T (7 , -2) , U (2 , 0)

- Lets find the slope of the 4 sides two find which of them are the

 parallel bases and which of them are the non-parallel bases

# The side RS

∵ m_{RS}=\frac{8-5}{1 - (-1)}=\frac{3}{2}

# The side ST

∵ m_{ST}=\frac{-2-8}{7-1}=\frac{-10}{6}=\frac{-5}{3}

# The side TU

∵ m_{TU}=\frac{0-(-2)}{2-7}=\frac{2}{-5}=\frac{-2}{5}

# The side UR

∵ m_{UR}=\frac{5-0}{-1-2}=\frac{5}{-3}=\frac{-5}{3}

∵ The slope of ST = the slop UR

∴ ST// UR

∴ The parallel bases are ST and UR

∴ The nonparallel sides are RS and TU

- Lets find the midpoint of RS and TU to find the equation of the

 median of the trapezoid

∵ The median of a trapezoid is a segment that joins the midpoints of

   the nonparallel sides

∵ The midpoint of RS = (\frac{-1+1}{2},\frac{5+8}{2})=(0,\frac{13}{2})

∵ The median is parallel to both bases

∴ The slope of the median equal the slopes of the parallel bases = -5/3

∵ The form of the equation of a line is y = mx + c

∴ The equation of the median is y = -5/3 x + c

- To find c substitute x , y in the equation by the coordinates of the

  midpoint of RS  

∵ The mid point of Rs is (0 , 13/2)

∴ 13/2 = -5/3 (0) + c

∴ 13/2 = c

∴ The equation of the median is y = -5/3 x + 13/2

- Multiply the two sides by 6 to cancel the denominator

∴ The equation of the median is 6y = -10x + 39

- Add 10x to both sides

∴ The equation of the median is 10x + 6y = 39

* The equation of the median of the trapezoid is 10x + 6y = 39

7 0
3 years ago
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