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Lubov Fominskaja [6]
3 years ago
15

Explain why converting from meters to centimeters uses a different exponent than converting from meters to millimeters.

Mathematics
2 answers:
MissTica3 years ago
8 0

Answer:

Well, centimetre and millimetre both are same smaller unit than the metre.

So, to convert from metre to millimetre a centimetre, we have to multiply by a number greater than 1 .

1m = 100cm

1m = 1000mm

So multiply by 100 or 10^2 to convert from metre to centimetre .

And multiply by 1000 or 10^3 to convert from metre to millimetre .

Step-by-step explanation:

hope it helps

~Adrianna

jekas [21]3 years ago
4 0

Converting from meter to centimeter uses a exponent of 2 and converting from meter to millimeter uses a exponent of 3

<h3><u>Solution:</u></h3>

The different units of length conversion charts are given as:

kilometre (km)

Hectometre (hm)

Decametre (dam)

Metre (m)

Decimetre (dm)

Centimetre (cm)

millimeter (m)

<em><u>Converting from meters to centimeters:</u></em>

From above listed units, we can observe meter is bigger unit than centimeter

So to convert from meter to centimeter, we have to move two times to reach centimeter in above listed units

So we have to multiply the value by 100 or 10 to power 2

1 meter = 100 cm

1 meter = 10^2 cm

So converting from meter to centimeter uses a exponent of 2

<em><u>Converting from meter to millimeter:</u></em>

Similarly using the above chart, we can say millimeter is smaller than meter.

So to convert from meter to millimeter, we have to move three times to reach millimeter in above listed units

In this, when we convert from meter to millimeter, we have to multiply the value by 1000

1 meter = 1000 millimeter

1 meter = 10^3 millimeter

So converting from meter to millimeter uses a exponent of 3

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Step-by-step explanation:

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A coin is tossed twice. What is the probability of getting a tail in the first toss and a tail in the second toss?
skelet666 [1.2K]

Answer:

<h2>1/4 Chances</h2><h2>25% Chances</h2><h2>0.25 Chances (out of 1)</h2>

Step-by-step explanation:

Two methods to answer the question.

Here are presented to show the advantage in using the product rule given above.

<h2>Method 1:Using the sample space</h2>

The sample space S of the experiment of tossing a coin twice is given by the tree diagram shown below

The first toss gives two possible outcomes: T or H ( in blue)

The second toss gives two possible outcomes: T or H (in red)

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tree diagram in tossing a coin twice

The event E : " tossing a coin twice and getting two tails " as a set is given by

          E={(T,T)}

with n(E)=1 where n(E) is the number of elements in the set E

Use the classical probability formula to find P(E) as:

          P(E)=n(E)n(S)=14

<h2>Method 2: Use the product rule of two independent event</h2>

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with the probabilities of each event A and B given by

          P(A)=12 and P(B)=12

Event E occurring may now be considered as events A and B occurring. Events A and B are independent and therefore the product rule may be used as follows

        P(E)=P(A and B)=P(A∩B)=P(A)⋅P(B)=12⋅12=14

NOTE If you toss a coin a large number of times, the sample space will have a large number of elements and therefore method 2 is much more practical to use than method 1 where you have a large number of outcomes.

We now present more examples and questions on how the product rule of independent events is used to solve probability questions.

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