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Lubov Fominskaja [6]
3 years ago
15

Explain why converting from meters to centimeters uses a different exponent than converting from meters to millimeters.

Mathematics
2 answers:
MissTica3 years ago
8 0

Answer:

Well, centimetre and millimetre both are same smaller unit than the metre.

So, to convert from metre to millimetre a centimetre, we have to multiply by a number greater than 1 .

1m = 100cm

1m = 1000mm

So multiply by 100 or 10^2 to convert from metre to centimetre .

And multiply by 1000 or 10^3 to convert from metre to millimetre .

Step-by-step explanation:

hope it helps

~Adrianna

jekas [21]3 years ago
4 0

Converting from meter to centimeter uses a exponent of 2 and converting from meter to millimeter uses a exponent of 3

<h3><u>Solution:</u></h3>

The different units of length conversion charts are given as:

kilometre (km)

Hectometre (hm)

Decametre (dam)

Metre (m)

Decimetre (dm)

Centimetre (cm)

millimeter (m)

<em><u>Converting from meters to centimeters:</u></em>

From above listed units, we can observe meter is bigger unit than centimeter

So to convert from meter to centimeter, we have to move two times to reach centimeter in above listed units

So we have to multiply the value by 100 or 10 to power 2

1 meter = 100 cm

1 meter = 10^2 cm

So converting from meter to centimeter uses a exponent of 2

<em><u>Converting from meter to millimeter:</u></em>

Similarly using the above chart, we can say millimeter is smaller than meter.

So to convert from meter to millimeter, we have to move three times to reach millimeter in above listed units

In this, when we convert from meter to millimeter, we have to multiply the value by 1000

1 meter = 1000 millimeter

1 meter = 10^3 millimeter

So converting from meter to millimeter uses a exponent of 3

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Natalka [10]

Answer:

Weight = \frac{23}{2}

Step-by-step explanation:

Given

Weight of Pinata = 11/4 lb

Weight of candies = 3/8, 3/8, 1/2 , 1/2, 1/2, 3/4, 3, 11/4

Required

Weight of Pinata when filled with candies

To solve this question, we simply need to add all weights together

First, we need to add up the weight of the candies

Candies =  \frac{3}{8} + \frac{3}{8} + \frac{1}{2}+ \frac{1}{2}+ \frac{1}{2}+ \frac{3}{4} + 3 + \frac{11}{4}

Take LCM

Candies = \frac{3 + 3 + 4 +4 + 4 + 6 + 24 + 22}{8}

Candies = \frac{70}{8}

Simplify:

Candies = \frac{35}{4}

Next; Add the weight of the candies to the weight of pinata

Weight = Candies + Pinata

Weight = \frac{35}{4} + \frac{11}{4}

Take LCM

Weight = \frac{35 + 11}{4}

Weight = \frac{46}{4}

Simplify

Weight = \frac{23}{2}

<em>Hence, the weight of the Pinata after it is filled with candies is 23/2 lb</em>

4 0
4 years ago
I got most of them but I need help on those 3
Vadim26 [7]
Using Pythagoras:-

x^2  = 6^2 + (sqrt18)^2
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3 0
3 years ago
5 m<br>3 m<br>6m<br>8m<br>what is the S.A.?​
Sergio [31]

Answer:

6m

Step-by-step explanation:

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3 years ago
Now suppose instead that Jane withdraws $500 from her checking account and uses $300 of this money to pay her federal income tax
zysi [14]

Answer:

Step-by-step explanation:

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5 0
3 years ago
4, Find a number x such that x = 1 mod 4, x 2 mod 7, and x 5 mod 9.
olchik [2.2K]

4, 7 and 9 are mutually coprime, so you can use the Chinese remainder theorem.

Start with

x=7\cdot9+4\cdot2\cdot9+4\cdot7\cdot5

Taken mod 4, the last two terms vanish and we're left with

x\equiv63\equiv64-1\equiv-1\equiv3\pmod4

We have 3^2\equiv9\equiv1\pmod4, so we can multiply the first term by 3 to guarantee that we end up with 1 mod 4.

x=7\cdot9\cdot3+4\cdot2\cdot9+4\cdot7\cdot5

Taken mod 7, the first and last terms vanish and we're left with

x\equiv72\equiv2\pmod7

which is what we want, so no adjustments needed here.

x=7\cdot9\cdot3+4\cdot2\cdot9+4\cdot7\cdot5

Taken mod 9, the first two terms vanish and we're left with

x\equiv140\equiv5\pmod9

so we don't need to make any adjustments here, and we end up with x=401.

By the Chinese remainder theorem, we find that any x such that

x\equiv401\pmod{4\cdot7\cdot9}\implies x\equiv149\pmod{252}

is a solution to this system, i.e. x=149+252n for any integer n, the smallest and positive of which is 149.

3 0
3 years ago
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