Answer:
The answer is C y= 2x-1
Step-by-step explanation:
Answer:
Are you graphing?
Step-by-step explanation:
In the problem, the first equation should be represented like this base on the variable given in the problem:
20p + 9t = 44.4
with that equation, the second equation would is given by this formula, in response with the additional number of paperback and textbook
21p + 14t = 51
to get the system equation in getting the mass of each variable, you should subtract the two equation to simplified the formula.
20p + 9t = 44.4
- 21p + 14t = 51
-------------------------
p + 5t = 6.6 // this is the system equation that could be use in getting the mass of each object
Answer:
No
Step-by-step explanation:
By using the Pythagoras theorem, it can be easily determined that whether the triangle is right triangle or not.
Thus, 
where where a and b are the legs and c is the hypotenuse.
Let a=6ft, b=21ft and c=23ft, then
which is not possible, therefore the given triangle is not right triangle because it does not satisfy the Pythagoras theorem.
You do the implcit differentation, then solve for y' and check where this is defined.
In your case: Differentiate implicitly: 2xy + x²y' - y² - x*2yy' = 0
Solve for y': y'(x²-2xy) +2xy - y² = 0
y' = (2xy-y²) / (x²-2xy)
Check where defined: y' is not defined if the denominator becomes zero, i.e.
x² - 2xy = 0 x(x - 2y) = 0
This has formal solutions x=0 and y=x/2. Now we check whether these values are possible for the initially given definition of y:
0^2*y - 0*y^2 =? 4 0 =? 4
This is impossible, hence the function is not defined for 0, and we can disregard this.
x^2*(x/2) - x(x/2)^2 =? 4 x^3/2 - x^3/4 = 4 x^3/4 = 4 x^3=16 x^3 = 16 x = cubicroot(16)
This is a possible value for y, so we have a point where y is defined, but not y'.
The solution to all of it is hence D - { cubicroot(16) }, where D is the domain of y (which nobody has asked for in this example :-).
(Actually, the check whether 0 is in D is superfluous: If you write as solution D - { 0, cubicroot(16) }, this is also correct - only it so happens that 0 is not in D, so the set difference cannot take it out of there ...).
If someone asks for that D, you have to solve the definition for y and find that domain - I don't know of any [general] way to find the domain without solving for the explicit function).
