Answer: 40

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Notice how WI = 12 is one-third of IL = 36
So AM is going to be one-third of ML = 30 making AM = 10
AL = AM+ML = 10+30 = 40
AL = 40

Or a more formal way to do it is to use ratios
AL/ML = WL/IL
AL/ML = (WI+IL)/IL
AL/30 = (12+36)/36
AL/30 = 48/36
36*AL = 30*48
36*AL = 1440
AL = 1440/36
AL = 40
Either way we get the same answer

3 0

4 years ago

Find the missing segment below brainly

Aleksandr-060686 [28]

Let it be x

$\\ \sf\longmapsto \dfrac{4}{10}=\dfrac{x}{12+x}$

$\\ \sf\longmapsto 4(12+x)=10x$

$\\ \sf\longmapsto 48+4x=10x$

$\\ \sf\longmapsto 10x-4x=48$

$\\ \sf\longmapsto 6x=48$

$\\ \sf\longmapsto x=\dfrac{48}{6}$

$\\ \sf\longmapsto x=8$

8 0

3 years ago

This problem involves a limit and the greatest integer function. My current guess is B. 1/3.5. I plugged 3.5 in for x. My numera

Drupady [299]

Yes your<span> answer is correct. Nice job.</span>

You should get 1 in the numerator when you plug in x = 3.5 and evaluate/simplify
In the denominator is simply 3.5

So you'll have 1/3.5 = 1/(7/2) = 2/7 as the final answer

7 0

3 years ago

Any suggestions or answers

KATRIN_1 [288]

The answer is D or a translation of 6 units to the right. This is because pre-image is shifted 6 units on the x axis to the right.

7 0

3 years ago