Answer:
Correct expression: 85 + 0.06(t - 400)
Correct earnings: $91
Step-by-step explanation:
The expression Joan wrote is incorrect because instead, $85, she put $400 as her base salary. The correct expression would be 85 + 0.06(t - 400), where 85 is her base pay in dollars, and t - 400 represents her sales in dollars exceeding $400.
If Joan's sales were $500, she would not make $424.90, but
85 + 0.06(t - 400)
85 + 0.06(500 - 400)
85 + 0.06(100)
85 + 6
$91
Hope this helps.
Cheers,
Andy
Answer:
135 grams
Step-by-step explanation:
you want to find the mass of only the grapes, not including the bowl. so in this case, you would subtract the mass of the bowl from the total mass. you do this because you dont need the mass of the bowl. 256g - 121g = 135g :)
(-4)(-2)= 8
8(-5)= -40
Answer: -40
Answer:
xy+2x+3y+6=xy-5 .............(1)
xy-3x+2y-6=xy.....,.,(2)
2x+3y=-11
-4x+2y=6
first equation multiply by 2
(2)*(2x+3y)=-11
4x+6y=-22
-4x+2y=6
8y=-16 y=(-2),,,,, x=(-2,5)
Step-by-step explanation:
According to this trigonometric function, −C gives you the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL:
![\displaystyle Phase\:[Horisontal]\:Shift → \frac{-\frac{2}{3}π}{2} = -\frac{π}{3} \\ Period → \frac{2}{2}π = π](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Phase%5C%3A%5BHorisontal%5D%5C%3AShift%20%E2%86%92%20%5Cfrac%7B-%5Cfrac%7B2%7D%7B3%7D%CF%80%7D%7B2%7D%20%3D%20-%5Cfrac%7B%CF%80%7D%7B3%7D%20%5C%5C%20Period%20%E2%86%92%20%5Cfrac%7B2%7D%7B2%7D%CF%80%20%3D%20%CF%80)
Therefore we have our answer.
Extended Information on the trigonometric function
![\displaystyle Vertical\:Shift → D \\ Phase\:[Horisontal]\:Shift → \frac{C}{B} \\ Period → \frac{2}{B}π \\ Amplitude → |A|](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Vertical%5C%3AShift%20%E2%86%92%20D%20%5C%5C%20Phase%5C%3A%5BHorisontal%5D%5C%3AShift%20%E2%86%92%20%5Cfrac%7BC%7D%7BB%7D%20%5C%5C%20Period%20%E2%86%92%20%5Cfrac%7B2%7D%7BB%7D%CF%80%20%5C%5C%20Amplitude%20%E2%86%92%20%7CA%7C)
NOTE: Sometimes, your vertical shift might tell you to shift your graph below or above the <em>midline</em><em> </em>where the amplitude is.
I am joyous to assist you anytime.
