Answer:B
I think we are in the same class lol
Step-by-step explanation:448 divided by 14= 32
448 divided by 16= 28
B=speed of boat in water
Y= Speed of current
B+y=32
B-y=28
32 + 28 =60
60 divided by 2 = 30
32 -30 =2
B=30
Y=2
Add my discord if you need more help Snapple#0141
<h2>
Hello!</h2>
The answer is:
The second option,
Zackery, because AB=BC
<h2>Why?</h2>
To identify which type of triangle is the triangle formed by the given points, first, we need to calculate the distance between the points.
So, finding the distances we have:
From A to B: (2,3) and (4,4)
From B to C: (4,4) and (6,3)
Hence, since the distances AB and BC are equal, the triangle is an isosceles triangle, so the answer is:
Zackery, because AB=BC
Have a nice day!
Y = (-1/9).x + 4
The slope m of the line perpendicular to y = (-1/9).x + 4 is equal to 9:
(if the product of 2 slopes = - 1, then the 2 lines are perpendicular)
y = 9x + b, Since it passes by the point (-1,0) , then:
0= 9(-1) + b and b = 9
Final equation:
y = 9x+9
Answer:
C. The rudely disagrees condition has a mean of 4.16 and a standard deviation of 0.85 while the politely disagrees condition has a mean of 3.82 and standard deviation of 0.97
Step-by-step explanation:
The given data is
x` Std. Dev
R. disagrees 4.16 0.854
P. disagrees 3.82 0.967
From this data we see that the R. disagrees has a mean of 4.16 and standard deviation of 0.854
while
the P. disagrees has a mean of 3.82 and standard deviation of 0.967.
Same figures are given only in option C because
Rounding 0.854 gives 0.85
Rounding 0.967 gives 0.97
So only option C is the best choice.
C. The R. Disagrees condition has a mean of 4.16 and a standard deviation of 0.85 while the P. Disagrees condition has a mean of 3.82 and standard deviation of 0.97
Hmm if I'm not mistaken, is just an "ordinary" annuity, thus
![\bf \qquad \qquad \textit{Future Value of an ordinary annuity} \\\\ A=pymnt\left[ \cfrac{\left( 1+\frac{r}{n} \right)^{nt}-1}{\frac{r}{n}} \right] \\\\\\](https://tex.z-dn.net/?f=%5Cbf%20%5Cqquad%20%5Cqquad%20%5Ctextit%7BFuture%20Value%20of%20an%20ordinary%20annuity%7D%0A%5C%5C%5C%5C%0AA%3Dpymnt%5Cleft%5B%20%5Ccfrac%7B%5Cleft%28%201%2B%5Cfrac%7Br%7D%7Bn%7D%20%5Cright%29%5E%7Bnt%7D-1%7D%7B%5Cfrac%7Br%7D%7Bn%7D%7D%20%5Cright%5D%0A%5C%5C%5C%5C%5C%5C)
![\bf \begin{cases} A= \begin{array}{llll} \textit{original amount}\\ \textit{already compounded} \end{array} & \begin{array}{llll} \end{array}\\ pymnt=\textit{periodic payments}\to &400\\ r=rate\to 10\%\to \frac{10}{100}\to &0.1\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, so once} \end{array}\to &1\\ t=years\to &14 \end{cases} \\\\\\ A=400\left[ \cfrac{\left( 1+\frac{0.1}{1} \right)^{1\cdot 14}-1}{\frac{0.1}{1}} \right] ](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Bcases%7D%0AA%3D%0A%5Cbegin%7Barray%7D%7Bllll%7D%0A%5Ctextit%7Boriginal%20amount%7D%5C%5C%0A%5Ctextit%7Balready%20compounded%7D%0A%5Cend%7Barray%7D%20%26%0A%5Cbegin%7Barray%7D%7Bllll%7D%0A%0A%5Cend%7Barray%7D%5C%5C%0Apymnt%3D%5Ctextit%7Bperiodic%20payments%7D%5Cto%20%26400%5C%5C%0Ar%3Drate%5Cto%2010%5C%25%5Cto%20%5Cfrac%7B10%7D%7B100%7D%5Cto%20%260.1%5C%5C%0An%3D%0A%5Cbegin%7Barray%7D%7Bllll%7D%0A%5Ctextit%7Btimes%20it%20compounds%20per%20year%7D%5C%5C%0A%5Ctextit%7Bannually%2C%20so%20once%7D%0A%5Cend%7Barray%7D%5Cto%20%261%5C%5C%0A%0At%3Dyears%5Cto%20%2614%0A%5Cend%7Bcases%7D%0A%5C%5C%5C%5C%5C%5C%0AA%3D400%5Cleft%5B%20%5Ccfrac%7B%5Cleft%28%201%2B%5Cfrac%7B0.1%7D%7B1%7D%20%5Cright%29%5E%7B1%5Ccdot%2014%7D-1%7D%7B%5Cfrac%7B0.1%7D%7B1%7D%7D%20%5Cright%5D%0A)
