All categories

3 years ago

What is the slope of a line that is parallel to the line joining (7,-5) and (-5,7)

Mathematics

1 answer:

brilliants [131]3 years ago

8 0

Answer:

Step-by-step explanation:

If two lines are parallel then they will have the same slope. So all you need to do is find the slope of the line that joins the two given points. You can use the slope formula $\frac{y_2-y_1}{x_2-x_1}$ . You can also graph the two points and use rise over run. $\frac{7-(-5)}{-5-7} =\frac{12}{-12}=-1$

You might be interested in

Tracie has saved $425 to spend during her 14 day vacation.About how much money can she spend each day?

mestny [16]

She can spend a little over 30 dollars each day, ($30.35)

8 0

2 years ago

Value of the underlined of 56

Elodia [21]

Anyway, the value of 5 is 50 and the value of 6 is 6 as in the ones place.

5 0

3 years ago

Read 2 more answers

Find the slope between the following two points: (3, 1), (5, 4).

gulaghasi [49]

Answer:

3/2 or 1.5

Step-by-step explanation:

$slope = \frac{4 - 1}{5 - 3} \\ \\ = \frac{3}{2} \\ \\ = 1.5$

4 0

2 years ago

Read 2 more answers

The end points of one side of a regular pentagon are (-1,4) and (2,3). What is the perimeter of the pentagon?

marissa [1.9K]

To determine the perimeter of the pentagon, you must first calculate a side length of it. Let's name the coordinates A(-1,4) and B(2,3).

To figure out how far the points are from each other, you have to use the distance formula:
$D_{AB} = \sqrt{( x_{2}-x_{1})^2+{(y_{2}-y_{1})^2}
$
$x_{1} =1, x_{2} =-2, y_{1} =2, y_{2} =3$
$D_{AB}= \sqrt{(2--1)^2+{(3-4)^2}$
D_{AB}= \sqrt{(2--1)^2+{(3-4)^2}
$D_{AB}= \sqrt{(2+1)^2+{(3-4)^2}$
$D_{AB}= \sqrt{(3)^2+(-1)^2}$
$D_{AB}= \sqrt{9+1}$
$D_{AB}= \sqrt{10}$

Now, the formula for the perimeter of a pentagon is
P = 5×side length

So...
Perimeter = 5× $\sqrt{10}$

The answer is (2)

8 0

3 years ago

Solve prt for t if i=105 p=700 r=0.05

Illusion [34]

I = prt
t = I/pr = 105/(700 x 0.05) = 105/35 = 3

Therefore, t = 3.

5 0

2 years ago