Answer:
In parallelogram ABCD
FD is perpendicular to BC
BE is perpendicular to CD
Consider triangle BEC and triangle DFC
FC = EC (Given)
Angle BEC = Angle DFC (=90°)
Angle BCE = Angle DCF (common)
Therefore triangle BEC is congruent to triangle DFC (AAS congruency)
DF = BE (CPCT)
Since the altitudes are equal their bases will also be equal
Therefore BC = DC
Therefore BC = DC = AD = AB
Therefore ABCD is a rhombus
Hope this helps!
Mark me as brainliest
The answer should be 12.2
7^2+10^2=c^2
49+100=c^2
149=c^2
12.2=c
The answer is 7/4 I added my work there sorry if it’s kinda messy
Answer:
sorry,this is not a question, has different answers
Answer:34
Step-by-step explanation:
