Answer:
To identify the problem
Explanation:
The first step in the problem-solving process is to identify the problem. It is not as simple as it sounds as different people may have different ideas of what the "problem" is. Clearly stating the problem and getting everyone involved to agree is an important first step.
Answer:
Explanation:
18 km/hr(1000 m/km) / (3600 s/hr) = 5 m/s
36 km/hr = 10 m/s
v² = u² + 2as
a = (v² - u²)/2s
a = (10² - 5²)/2(1000) = 0.0375 m/s²
v² = 10² + 2(0.0375)(1000)
v² = 175
v = 13.22875... ≈ 13 m/s ≈ 48 km/hr
v = u + at
t = (v - u) / a
t = (10 - 5)/0.0375 = 133.333... 133 s
t = (13.22875 - 10) / 0.0375 = 86.1 s
Answer: S2P6
The electronic configuraiton of given elements are as follows:
Ne =<span><span><span>[<span>He</span><span>]2</span></span><span>s2 2</span><span>p6<span>
</span></span></span>Ar = </span><span><span><span>[<span>Ne</span><span>]3</span></span><span>s2 3</span><span>p6<span>
</span></span></span>Kr = </span><span><span>[<span>Ar</span><span>]4</span></span><span>s2 3</span><span>d10 4</span>p6</span>
As it can be seen that for all three elements, their outermost orbital are completely filled, that is it has both s orbital, p orbital and d orbital fulfilled. Noble or inert gas atoms like Neon, Argon, Krypton have fulfilled valence shell. Fulfilled outermost orbital is the most stable electronic state, hence all elements tends to achieve such stability. These noble gas elements are called inert gas because of their fulfilled outermost shell. This means they don't react easily or take part in eletron donating, receiving or sharing. This is because, for all other elements except inert gas atoms, their valence shell is incomplete and they tend to react by other atoms so as to complete their outermost shell , which we call as duplet (in case of Helium like) or Octet state. Such elements either donate some electrons or receive some to acheive such stable state..
Answer:
s_400 = 16.5 m
, s_700 = 29.4 m
Explanation:
The limit of the human eye's solution is determined by the diffraction limit that is given by the expression
θ = 1.22 λ / D
where you lick the wavelength and D the mediator of the circular aperture.
In our case, the dilated pupil has a diameter of approximately 8 mm = 8 10-3 m and the eye responds to a wavelength between 400 nm and 700 nm.
by introducing these values into the formula
λ = 400 nm θ = 1.22 400 10⁻⁹ / 8 10⁻³ = 6 10⁻⁵ rad
λ = 700 nm θ = 1.22 700 10⁻⁹ / 8 10⁻³-3 = 1.07 10⁻⁴ rad
Now we can use the definition radians
θ= s / R
where s is the supported arc and R is the radius. Let's find the sarcos for each case
λ = 400 nm s_400 = θ R
S_400 = 6 10⁻⁵ 275 10³
s_400 = 16.5 m
λ = 700 nm s_ 700 = 1.07 10⁻⁴ 275 10³
s_700 = 29.4 m
Turning on a light switch converts mechanical energy to electrical and radiant energy. So Mechanical energy
