Question

Now assume that two identical cars of mass m drive along a highway. One car approaches a curve of radius 2R at speed v. The second car approaches a curve of radius 6R at a speed of 3v. How does the magnitude F1 of the net force exerted on the first car compare to the magnitude F2 of the net force exerted on the second car? Answer Choices Below: A. F1 = 1/3F2 B. F1 = 3/4F2 C. F1 = F2 D. F1 = 3F2 E. F1 = 27F2

Answer 1

Answer:

$F_1 = 3F_2$

Explanation:

As we know that car is moving in the curve of given radius

So the force on that car is given as

$F = \frac{mv^2}{R}$

So for the first car we have

$F_1 = \frac{mv^2}{2R}$

for other car we will have

$F_2 = \frac{m(3v)^2}{6R}$

$F_2 = \frac{3mv^2}{2R}$

now we will have

$\frac{F_2}{F_1} = \frac{1}{3}$

$F_1 = 3F_2$