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Dmitry [639]
3 years ago
14

Which equation is true? I. (32 ÷ 8 – 2)6 = (32 – 1)2 II. 72 ÷ 9·4 = 62 ÷ (6 + 3) II only Neither I nor II I only I and II

Mathematics
2 answers:
mixas84 [53]3 years ago
6 0

Answer:

Neither I nor II

Step-by-step explanation:

We will simplify both the sides of the given equations,

Equation I. (\frac{32}{8}-2)^{6}=(32-1)^{2}

i.e. (4}-2)^{6}=(31)^{2}

i.e. 2^{6}=(31)^{2}

i.e. 64=961, which is not true.

Equation II. \frac{72}{9\times 4}=\frac{62}{6+3}

i.e. \frac{72}{36}=\frac{62}{9}

i.e. 2 = 6.9, which is not true.

Hence, neither of the equations are true.

Umnica [9.8K]3 years ago
4 0

Answer: The answer is (b) Neither I nor II.


Step-by-step explanation: We are given two equations and we need to find which is true. Since it is a simple algebraic question, so we just need to follow BODMAS rule to check the equations.

The equations are as follows -  

(I)~~L.H.S=(\dfrac{32}{8}-2)6=(4-2)6=2\times 6=12.

R.H.S=(32-1)2=31\times 2=62.

Since L.H.S ≠ R.H.S, so this equation is not correct.

(II)~~L.H.S=\dfrac{72}{9\times 4}=2.

R.H.S=\dfrac{62}{6+3}=\dfrac{62}{9}.

Since L.H.S ≠ R.H.S, so this equation is also not correct.

Thus, the correct option is (b) Neither I nor II.


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Step-by-step explanation:

The question is incomplete. Here is the complete question.

The upper-left coordinates on a rectangle are (−5,6) and the upper-right coordinates are (−2,6). The rectangle has a perimeter of 16units. Draw the rectangle on the coordinate plane below.

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