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Nana76 [90]
3 years ago
7

HELP please! This is for a test.

Mathematics
2 answers:
Svetllana [295]3 years ago
6 0

Answer:

D

Step-by-step explanation:

Oxana [17]3 years ago
3 0

Answer:

D 1.54 feet per week is the awnser

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Which of these graphs represents a function?
Vlada [557]

Answer:

{ \tt{graph \: y \:and \:graph\: z}}

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The sum of two numbers is 64 and the difference is 6. What are the numbers?
Ne4ueva [31]

Answer:

29 and 35

Step-by-step explanation:

x+y=64

x-y=6

Solve by substitution.

x=6+y

6+y+y=64

6+2y=64

y=29

Then plug in 29 for y.

x+29=64 ......35

7 0
3 years ago
Can somebody please help me with these two questions?
vovikov84 [41]
The answer to 25. is A
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3 years ago
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Inveres laplace transform (3s-14)/s^2-4s+8​
Olenka [21]

Complete the square in the denominator.

s^2 - 4s + 8 = (s^2 - 4s + 4) + 4 = (s-2)^2 + 4

Rewrite the given transform as

\dfrac{3s-14}{s^2-4s+8} = \dfrac{3(s-2) - 8}{(s-2)^2+4} = 3\times\dfrac{s-2}{(s-2)^2+2^2} - 4\times\dfrac{2}{(s-2)^2+2^2}

Now take the inverse transform:

L^{-1}_t\left\{3\times\dfrac{s-2}{(s-2)^2+2^2} - 4\times\dfrac{2}{(s-2)^2+2^2}\right\} \\\\ 3L^{-1}_t\left\{\dfrac{s-2}{(s-2)^2+2^2}\right\} - 4L^{-1}_t\left\{\dfrac{2}{(s-2)^2+2^2}\right\} \\\\ 3e^{2t} L^{-1}_t\left\{\dfrac s{s^2+2^2}\right\} - 4e^{2t} L^{-1}_t\left\{\dfrac{2}{s^2+2^2}\right\} \\\\ \boxed{3e^{2t} \cos(2t) - 4e^{2t} \sin(2t)}

5 0
3 years ago
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