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Vsevolod [243]
3 years ago
5

Can someone help me here​

Mathematics
1 answer:
bearhunter [10]3 years ago
3 0

Answer:

1.

Step-by-step explanation:

1. sin 241 = sin(61 + π) = -sin61 = -t^(1/2)

2. sin^2 + cos^2 =1, cos 61= (1-t)^(1/2)

3. [2sin^2 (x)sin(x) +2cos^2 (x)sin(x)]/2cos(x) = 2sin(x) / 2cos(x) = tan(x)

4. tan (x), x do not equal to (π/2 +or- kπ)

x do not equal to 90,270。

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Step-by-step explanation:

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<u><em>Note:</em></u><em> As you have missed to mention the first four terms of the Arithmetic sequence. So, I am randomly assuming that first four terms of the arithmetic sequence be 1, 3, 5, 7... This would anyhow make you understand the concept. So, I am solving your query based on assuming the first four terms of an Arithmetic sequence as 1, 3, 5, 7...</em>

Part A)

<em><u>What is the next term of this sequence?</u></em>

Answer:

{\displaystyle \ a_{5}=9 is the next term i.e. 5th term of the arithmetic sequence <em>1, 3, 5, 7...</em>

Step-by-step explanation:

Considering the Arithmetic sequence with fist four terms

<em> 1, 3, 5, 7...</em>

As we know that a sequence is termed as arithmetic sequence of numbers if the difference of any two consecutive terms of the sequence remains constant.

For instance, <em> 1, 3, 5, 7... </em>will be an arithmetic sequence having the common difference 2. Common difference is denoted by 'd'.

So,

Given the sequence

<em>1, 3, 5, 7...</em>

d=3-1=2,d=5-3=2

As a_{1} = 1 and d = 2

The next term i.e. 5th term can be found by using the nth term of the sequence.

So, consider the nth term of the sequence {\displaystyle a_{n}

{\displaystyle \ a_{n}=a_{1}+(n-1)d}

Putting n=5 in, a_{1} = 1 and d = 2  in {\displaystyle \ a_{n}=a_{1}+(n-1)d} to find the 5th term.

{\displaystyle \ a_{n}=a_{1}+(n-1)d}

{\displaystyle \ a_{5}=1+(5-1)2}

{\displaystyle \ a_{5}=1+(4)2}

{\displaystyle \ a_{5}=9

So, {\displaystyle \ a_{5}=9 is the next term i.e. 5th term of the arithmetic sequence <em>1, 3, 5, 7...</em>

Part B)

<u><em>Writing down an expression,  in terms of n for the nth term of the sequence</em></u>

consider the nth term of the sequence {\displaystyle a_{n}

{\displaystyle \ a_{n}=a_{1}+(n-1)d}

Here, a_{1} is the first term, d is the common difference.

For example,

Given the sequence

<em>1, 3, 5, 7...</em>

d=3-1=2,d=5-3=2

As a_{1} = 1 and d = 2

The next term i.e. 5th term can be found by using the nth term of the sequence.

So, consider the nth term of the sequence {\displaystyle a_{n}

{\displaystyle \ a_{n}=a_{1}+(n-1)d}

Putting n=5 in, a_{1} = 1 and d = 2  in {\displaystyle \ a_{n}=a_{1}+(n-1)d} to find the 5th term.

{\displaystyle \ a_{n}=a_{1}+(n-1)d}

{\displaystyle \ a_{5}=1+(5-1)2}

{\displaystyle \ a_{5}=1+(4)2}

{\displaystyle \ a_{5}=9

Keywords: arithmetic sequence, nth term, common difference

Learn more abut arithmetic sequence, nth term and common difference from brainly.com/question/12227567

#learnwithBrainly

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