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Semmy [17]
3 years ago
9

Y = -4x + 8 Y=3/5x - 6/5

Mathematics
1 answer:
VladimirAG [237]3 years ago
5 0

Answer:

x=2 and y=0

Step-by-step explanation:

Rewrite equations:

y=−4x+8;y=

3

5

x+

−6

5

Step: Solvey=−4x+8for y:

y=−4x+8

Step: Substitute−4x+8foryiny=

3

5

x+

−6

5

:

y=

3

5

x+

−6

5

−4x+8=

3

5

x+

−6

5

−4x+8+

−3

5

x=

3

5

x+

−6

5

+

−3

5

x(Add (-3)/5x to both sides)

−23

5

x+8=

−6

5

−23

5

x+8+−8=

−6

5

+−8(Add -8 to both sides)

−23

5

x=

−46

5

−23

5

x

−23

5

=

−46

5

−23

5

(Divide both sides by (-23)/5)

x=2

Step: Substitute2forxiny=−4x+8:

y=−4x+8

y=(−4)(2)+8

y=0(Simplify both sides of the equation)

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A pile of 10 000 paper is 89 cm thick. How thick is one sheet of paper?
Iteru [2.4K]

Answer:

0.0089 cm

Step-by-step explanation:

89/10 000

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8 0
3 years ago
Suppose a couple planned to have three children. Let X be the number of girls the couple has.
sesenic [268]

Answer:

a) {GGG, GGB, GBG, BGG, BBG, BGB, GBB, BBB}

b) {0,1,2,3}

c)

P(X=2) = \dfrac{3}{8}

d)

P(\text{3 boys}) = \dfrac{1}{8}

Step-by-step explanation:

We are given the following in the question:

Suppose a couple planned to have three children. Let X be the number of girls the couple has.

a) possible arrangements of girls and boys

Sample space:

{GGG, GGB, GBG, BGG, BBG, BGB, GBB, BBB}

b) sample space for X

X is the number of girls couple has. Thus, X can take the values 0, 1, 2 and 3 that is 0 girls, 1 girl, 2 girls and three girls from three children.

Sample space: {0,1,2,3}

c) probability that X=2

P(X=2)

That is we have to compute the probability that couple has exactly two girls.

\text{Probability} = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}

Favorable outcome: {GGB, GBG, BGG}

P(X=2) =\dfrac{3}{8}

d) probability that the couple have three boys.

Favorable outcome: {BBB}

P(BBB) = \dfrac{1}{8}

8 0
3 years ago
If R is the midpoint of PS with PR = 7x + 23 and RS= 13x-19 then find PS
Rainbow [258]

If R is the midpoint of PS, then PR = RS -- (1)

Also, PR + RS = PS -- (2)

__________________

PR + RS = PS

7x + 23 + 13x - 19 = PS

__________________

Now, PR = PS

7x + 23 = 13x - 19

7x - 13x = -19 - 23

-6x = -42

x = -42/-6

x = 7

__________________

PS = 7x + 23 + 13x - 19

PS = 7(7) + 23 + 13(7) - 19

PS = 49 + 23 + 91 - 19

<u>PS </u><u>=</u><u> </u><u>1</u><u>4</u><u>4</u><u> </u>

Hope it helps!

꧁✿ ᴿᴬᴵᴺᴮᴼᵂˢᴬᴸᵀ2222 ✬꧂

7 0
2 years ago
The circle given by
mixer [17]
Typically, the equation of a circle is given like this: (x-h)^2 + (y-k)^2 = r^2, where r is the radius of the circle and the point (h,k) is the center. To find the value k, you need to put the first equation you have into this form. Standard form requires that you only have the1 y variable, as seen in the parentheses, so you first need to complete the square.

x^2 + y^2 - 2y = 11
x^2 + y^2 - 2y +1 = 11 + 1
x^2 + (y - 1)^2 = 12

And that puts the equation in standard form. k = 1.
5 0
3 years ago
Read 2 more answers
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