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Semmy [17]
3 years ago
9

Y = -4x + 8 Y=3/5x - 6/5

Mathematics
1 answer:
VladimirAG [237]3 years ago
5 0

Answer:

x=2 and y=0

Step-by-step explanation:

Rewrite equations:

y=−4x+8;y=

3

5

x+

−6

5

Step: Solvey=−4x+8for y:

y=−4x+8

Step: Substitute−4x+8foryiny=

3

5

x+

−6

5

:

y=

3

5

x+

−6

5

−4x+8=

3

5

x+

−6

5

−4x+8+

−3

5

x=

3

5

x+

−6

5

+

−3

5

x(Add (-3)/5x to both sides)

−23

5

x+8=

−6

5

−23

5

x+8+−8=

−6

5

+−8(Add -8 to both sides)

−23

5

x=

−46

5

−23

5

x

−23

5

=

−46

5

−23

5

(Divide both sides by (-23)/5)

x=2

Step: Substitute2forxiny=−4x+8:

y=−4x+8

y=(−4)(2)+8

y=0(Simplify both sides of the equation)

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3/16+3/16=6/16

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Step-by-step explanation:

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How does the definition of the prefixes mono-,bi-, and tri- help when naming polynomials
Leviafan [203]

Answer:

They let you know the number of numbers there are/will be.

Step-by-step explanation:

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and tri, being three, means there are three numbers in the equation.

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Which equation represents a circle that contains the point (-5, 3) and has a center at (-2, 1)? Distance formula: vaa -02 (x - 1
natali 33 [55]

Given:

The center of the circle = (-2,1).

Circle passes through the point (-5,3).

To find:

The equation of the circle.

Solution:

Radius is the distance between the center of the circle and any point on the circle. So, radius of the circle is the distance between the points (-2,1) and (-5,3).

Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

r=\sqrt{(-5-(-2))^2+(3-1)^2}

r=\sqrt{(-5+2)^2+(2)^2}

r=\sqrt{(-3)^2+(2)^2}

On further simplification, we get

r=\sqrt{9+4}

r=\sqrt{13}

The standard form of a circle is:

(x-h)^2+(y-k)^2=r^2

Where, (h,k) is the center of the circle and r is the radius of the circle.

Substitute h=-2, k=1 and r=\sqrt{13}.

(x-(-2))^2+(y-1)^2=(\sqrt{13})^2

(x+2)^2+(y-1)^2=13

Therefore, the equation of the circle is (x+2)^2+(y-1)^2=13.

8 0
3 years ago
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