Answer:
2 over 10 and 4 over 20
Step-by-step explanation:
<h2>10=)21 I know it is right </h2>
The answer is 75 degrees I believe.
45 + 60 + x = 180
I’m pretty sure I’m correct but I’m so sorry if I’m wrong.
Considering the function for the remaining amount of cesium in the atmosphere, F(x) = 1000×0.5^(x/30), we have;
First part:
- The area will be safe again in about 100 years time.
Second part;
- The y-intercept is at the start of the measurement
Third part;
- The function is a decay function
<h3>Which method can be used to evaluate the given function?</h3>
First part;
The given function for the remaining amount of cesium is presented as follows;

When 100 kg. of cesium is remaining, we have;

Which gives;


- Therefore, the area will be safe again in approximately 100 years.
Second part;
The y-intercept is given by the point where <em>x </em>= 0
At the y-intercept, we therefore have;

At the y-intercept, the amount of cesium remaining, F(x) is 1,000, which is the initial amount of cesium.
- The y-intercept is therefore, at the start of the measurement, where 1000 kg. is present in the atmosphere.
Third part;
The amount of cesium remaining F (x) decreases as the time, <em>x</em>, increases, the function is therefore a decay function.
Learn more about exponential functions here;
brainly.com/question/2456547
#SPJ1