Answer:
She should earn 225 dollars.
Step-by-step explanation:
I know this because 50 ÷ 4 = 12.5 and 12.5 × 18 = 225.
Answer:
The value is 
The correct option is a
Step-by-step explanation:
From the question we are told that
The margin of error is E = 0.05
From the question we are told the confidence level is 95% , hence the level of significance is

=> 
Generally from the normal distribution table the critical value of is

Generally since the sample proportion is not given we will assume it to be

Generally the sample size is mathematically represented as
![n = [\frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * \^ p (1 - \^ p )](https://tex.z-dn.net/?f=n%20%3D%20%5B%5Cfrac%7BZ_%7B%5Cfrac%7B%5Calpha%20%7D%7B2%7D%20%7D%7D%7BE%7D%20%5D%5E2%20%2A%20%5C%5E%20p%20%281%20-%20%5C%5E%20p%20%29%20)
=> ![n = [\frac{ 1.96 }{0.05} ]^2 *0.5 (1 - 0.5)](https://tex.z-dn.net/?f=n%20%3D%20%5B%5Cfrac%7B%201.96%20%7D%7B0.05%7D%20%5D%5E2%20%2A0.5%20%281%20-%200.5%29%20)
=> 
Generally the margin of error is mathematically represented as

Generally if the level of confidence increases, the critical value of
increase and from the equation for margin of error we see the the critical value varies directly with the margin of error , hence the margin of error will increase also
So If the confidence level is increased, then the sample size would need to increase because a higher level of confidence increases the margin of error.
Simply substitute the point into the given equation; as there is one variable, you only need one point and so one is given. When done so, you shall get b=4
Step-by-step explanation: A line, ray, or line segment (referred to as segment) that is perpendicular to a given segment at its midpoint is called a perpendicular bisector. ... In the diagram above, RS is the perpendicular bisector of PQ, since RS is perpendicular to PQ and PS≅QS. Additionally, since PS≅QS, point S is the midpoint of PQ.
Answer:
880 feet per hour.
Step-by-step explanation:
26 inches to foot = 2.2
9 seconds to hour = 0.0025
2.2/0.0025 = 880 feet per hour.
If you need any more help please let me know and i will make a video for you.