A and B lie on the line, yes, but what specifically are you supposed to do? Looks like your problem statement was cut off before you'd finished typing it in.
You say your line passes thru (-2,5) and has a slope of 2/3? Then, using the point-slope formula,
y-5 = (2/3)(x+2) This is the general equation for your line.
Now let's play around with B(-2,y). Suppose we subst. the x-coordinate of B, which is -2, into the equation y-5 = (2/3)(x+2); we get y-5 = (2/3)(-2+2) = 0. This tells us that y must be 5. But we already knew that!!
So, please review the original problems with its instructions and this discussion and tell me what you need to know from this point on.
Let f(x) = x² + 6x²-x+ 5 then ,
number to be added be P
then,
f(x) = x² + 6x²-x+ 5 +P
According to the qn,
(x+3) is exactly divisible by zero then,
R=0
comparing .. we get a= -3
now by remainder theorm
R=f(a)
0=f(-3)
0=(-3)² + 6(-3)²-(-3)+ 5 + P
0= 9 + 54 + 3 + 5 + P
-71=P
therefore, -71 should be added.
Hope you understand
Answer:
0 People initially had the cold.
6 People will have it after 2 days.
Step-by-step explanation:
To find out how many people had it initially, plug 0 in for x (implying 0 days later.)
C= 1*3(0)
C= 1*0
C=0
Nobody had the cold initially.
To find out how many people had it after 2 days, plug 2 in for x. (implying 2 days later.)
C= 1*3(2)
C= 1*6
C=6
Therefore 6 people had the cold after 2 days.
I hope this helps!
Step-by-step explanation:
line a is perpendicular to B.
if the slope of line A is -3/4 what is the line of B
