Answer:
360
Step-by-step explanation:
The easiest way is to graph it based upon the slope (m) and y-intercept (b), in the standard slope-intercept form: y = m (x) + b.
The line above intercepts the y-axis at y = -2, which is b. The slope (m) = rise/run = (y2-y1)/(x2-x1 ); so for the point (-4, 2) to (-6, 4) is:
(4-2)/(-6--4) = 2/(-6+4) = 2/-2 = -1.
So one form of the equation would be:
y = -1x - 2
Now the other form of an equation is point-slope: y-k = m (x-h), where the point is at (h, k)
and if we pick -5 for x (bc 5 it listed in 3 of the answers), the y at x=-5 looks like around +3
so we get: y-k = -1 (x--5)...
y-3 = -(x+5)... therefore D) is the correct answer:
30 degrees due to the fact that all triangles interior angles add up to 180 degrees and there are two other angles meaning it is 30 degrees
The idea is to use the tangent line to
at
in order to approximate
.
We have


so the linear approximation to
is

Hence
and
.
Then

The answer is x=20. You isolate the square root. Eliminate the radical on the left handside. And then solve it!