All categories

3 years ago

What is the domain of the relation? {(-4, -1), (-2, 1), (0, 1), (2, 3), (4, 0)}

Mathematics

1 answer:

iris [78.8K]3 years ago

5 0

The domain is usually always the first number of the pair so for example it would be -4, -2, 1...

You might be interested in

The table below represents a linear function f(x) and the equation represents a function g(x):

Elza [17]

Answer:

(a) The slope of f(x) is greater than the slope of g(x)

(b) f(x) has a greater y intercept

Step-by-step explanation:

Given

$\begin{array}{cc}x & {f(x)} & -1&-9&0&-1&1&7 \ \end{array}$

$g(x) = 3x - 2$

Solving (a): Compare the slopes

The slope (m) of f(x) is calculated as;

$m = \frac{f(x_2) - f(x_1)}{x_2 - x_1}$

This gives:

$m = \frac{f(0) - f(1)}{0 - 1}$

$m = \frac{f(0) - f(1)}{- 1}$

Substitute values for f(0) and f(1)

$m = \frac{-1 - 7}{- 1}$

$m = \frac{-8}{- 1}$

$m = 8$

The slope of g(x) can be gotten using the following comparison

$g(x) = mx + b$

$m \to slope$

So:

$g(x) = 3x -2$

$m = 3$

$m_{f(x)} > m_{g(x)}$

Solving (b): Compare the y intercept

y intercept is when $x = 0$

From the table of f(x)

$f(0) = -1$

From the equation of g(x)

$g(x) = 3x -2$

$g(0) = 3*0-2$

$g(0) =-2$

6 0

3 years ago

I'm having a problem finding the points

Ivenika [448]

The points are (-3,3) and (2,2) then you use distance formula to find the distance between them

4 0

3 years ago

Read 2 more answers

The equation of three other functions are given which function or functions have a slope equal to the slope of Function 1

ratelena [41]

Answer:

See Explanation

Step-by-step explanation:

Required

Function(s) with the same slope as function 1

The question is incomplete as function 1 and the three additional functions are not given.

However, I will provide a general explanation.

A slope is represented as:

$y = mx + b$

Where

$m \to$ slope

So, considering the following equations

$y = 2x + 3$

$y = \frac{3x}{2} + 9$

$y = 2x - 5$

$y = -2x + 3$

The following equations have the same slope

$y = 2x + 3$ and $y = 2x - 5$

Because: $y = mx + b$ implies that:

$m = 2$ for $y = 2x + 3$ and $y = 2x - 5$

5 0

3 years ago

Find the exact value of sin(-15)

koban [17]

$1)\ \ \ sin(- \alpha )=-sin \alpha \\2)\ \ \ cos2 \alpha =1-2sin^2 \alpha \ \ \ \Rightarrow\ \ \ 2sin^2 \alpha =1-cos2 \alpha \\\\ \Rightarrow\ \ \ sin \alpha = \sqrt{\frac{\big{1-cos2 \alpha}}{\big{2}}} \\\\\\sin(-15^0)=-sin15^0=-\sqrt{\frac{\big{1-cos30^0}}{\big{2}}} =-\sqrt{\frac{\big{1- \frac{ \sqrt{3} }{2} }}{\big{2}}} =-\sqrt{\frac{\big{2- \sqrt{3}}}{\big{4}}} =\\\\ =- \frac{1}{2} \sqrt{2- \sqrt{3}}$

7 0

4 years ago

Question 2

julia-pushkina [17]

Answer:

A. C = (d-ab)/a

Step-by-step explanation:

a(c + b) = d

a(c + b)/a = d/a

c + b = (d/a)

c = (d/a) - b

a(c + b) = d

ac + ab = d

ac = d - ab

ac/a = d/a - ab/a

c = (d/a) - b

5 0

3 years ago