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grigory [225]
4 years ago
7

What is the domain of the relation? {(-4, -1), (-2, 1), (0, 1), (2, 3), (4, 0)}

Mathematics
1 answer:
iris [78.8K]4 years ago
5 0
The domain is usually always the first number of the pair so for example it would be -4, -2, 1...
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Create an equivalent expression for 4t-18-t+2t+20
alexandr1967 [171]

Answer:

5t + 2

General Formulas and Concepts:

<u>Algebra I</u>

  • Combining Like Terms

Step-by-step explanation:

<u>Step 1: Define Expression</u>

4t - 18 - t + 2t + 20

<u>Step 2: Simplify</u>

  1. Combine like terms (t):                    5t - 18 + 20
  2. Combine like terms (Z):                   5t + 2
6 0
3 years ago
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What is the answer???
a_sh-v [17]

Answer:

AC < CD

RQS > QST

Step-by-step explanation:

The side that sees the bigger angle has a bigger length and so the side that sees the smaller angle has the smaller length in size.

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3 years ago
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I only have two questions
Lady bird [3.3K]

2 \times 7 - 5 = 9
6 \times 3 = 18 + 23 = 41 + 7 \div 3341.21 - 3 = 38.21
7 0
4 years ago
Donovan fed his dog for 5 weeks and used 12 lbs of dog food, at the same rate. How much dog food will he use in 8 weeks?
Anna [14]

Answer:

19.2 lbs of dog food in 5 weeks

Step-by-step explanation:

12 divided by 5 is 2.4

So that means each week the dog consumes 2.4 lbs of food each week.

If we want to see how much he eats in 8 weeks, we'd multiply 2.4 by 8, giving us 19.2

8 0
3 years ago
A TEACHER IS CONSTRUCTING A MATHEMATICS TEST
Nuetrik [128]

The number of ways of constructing questions from the pool of 28 questions if her test is to have 3 difficult, 4 average and 3 easy questions is  924, 000 ways

<h3>How to determine the combination</h3>

Note that the formula for combination is given as;

Combination = \frac{n!}{r!(n-r)!}

From the information we have that;

There are 28 questions in the pool

The test should have a total of 10 questions;

6 difficult , 10 average and 12 easy questions

We are asked to determine the combination of;

3 difficult questions

4 average questions

3 easy questions

6C3 = \frac{6!}{3!(6-3)!}

6C3 = \frac{720}{36}

6C3 = 20

10C4 = \frac{10!}{4!(10-4)!}

10C4 = \frac{3628800}{17280}

10C4 = 210

12C4 = \frac{12!}{4!(12-4)!}

12C4 = 220

The number of ways of constructing the questions is

= 20 × 210 × 220

= 924, 000 ways

Thus, the number of ways of constructing questions from the pool of 28 questions if her test is to have 3 difficult, 4 average and 3 easy questions is  924, 000 ways

Learn more about combination here:

brainly.com/question/4658834

#SPJ1

7 0
2 years ago
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