2 years ago

How do I solve these?

Mathematics

1 answer:

Levart [38]2 years ago

5 0

The first answer (question 4) is 12 and the second answer (question 5) is 13 hope this helps!!!

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40=3x+x^2<br><br> How do I find the answer to this

tamaranim1 [39]

Answer:

x = -8, x = 5

Step-by-step explanation:

This can be solved using Factorization method:

$40 = 3x + {x}^{2} \\ \\ \implies \: {x}^{2} + 3x - 40 = 0 \\ \\ \implies \: {x}^{2} + 8x - 5x- 40 = 0 \\ \\ \implies \: x({x} + 8) - 5(x + 8) = 0 \\ \\ \implies \: ({x} + 8) (x - 5) = 0 \\ \\ \implies \: ({x} + 8) = 0 \: \: or \: \: (x - 5) = 0 \\ \\ \implies \: x = - 8 \: \: or \: \: x = 5 \\ \\ x = - 8, \: \: 5$