Let the numbers be x and y
According to the data : xy=-15 and x+y=-7
xy=-15
x+y=-7
y=-7-x
x(-x-7)=-15
y=-7-x
-x^2-7x=-15
y=-7-x
x^2+7x-15=0
y=-7-x
x=(-7±sqrt(7*7+4*15))/2
y=-7-x
x=(-7±sqrt(109<span>))/2
</span>
Goes to two systems.
1)
y=-7-x
x=(-7+sqrt(109<span>))/2
</span>
y=-7+3.5-sqrt(109<span>))/2
</span>x=(-7+sqrt(109<span>))/2
</span>
y=-3.5-sqrt(109<span>))/2
</span>x=(-7+sqrt(109<span>))/2
</span>
2)
y=-7-x
x=(-7-sqrt(109<span>))/2
</span>
y=-7+3.5+sqrt(109))/2
x=(-7-sqrt(109))/2
y=-3.5+sqrt(109))/2
x=(-7-sqrt(109<span>))/2</span>
They are both divisible by 2. 10/2=5 and 6/2=3. The ratio is 3:5
Answer:
See step by step
Step-by-step explanation:
1. First question, do they represent functions? The one o. the left is a function because if you do the vertical line test. It only passes through a point once so it is a function. while on the right if you do the vertical line test, it passes through a point twice so it not a function. For 2.. n other words, since the domain of this equation is all real numbers or negative infinity to positives infinity
let say x=1 and x=-1 and we use the equation

when we plug both those in we get

this means that we can have two different x-values to equal out to the same y value. This is the definition of a function. So the one on the right is a function.
However the one on the left is a relation. TO Prove it, the domain of that function is all real numbers equal to or greater than zero, so let use 4.


Since there are 2 possible answer choices as the y value, this isn't a function. It a relation. It maps a group of ordered sets to one x value. Which is the opposite of the function. So the one of the left is a relation
Answer:
hello, this is you math teacher! i am undercover on this app and you have been banned for cheating
Step-by-step explanation:
jkjk lol
19,008 I just used a calculator