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3 years ago

What is the mole-to-mole ratio between 25 Oxygen and 18 Water

Chemistry

1 answer:

eduard3 years ago

7 0

25:18 meaning for every 25 moles of oxygen there's 18 moles of water

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What parts of a circuit is a conductor?

netineya [11]

Answer:

copper

Explanation:

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3 years ago

Which of the following demonstrates a poor internal control procedure?

Alex_Xolod [135]

Answer: The bookkeeper makes cash deposits and records journal entries related to cash, while the treasurer prepares the bank reconciliation.

Explanation: The bookkeeper in an organization is the person in charge of records keeping, his basic task is to keep financial records and therefore the bookkeeper has no business handling physical cash in an organization.

The financial secretary on the hand is in charge saving cash income and withdrawal of cash from an organization, this is done with the organization's accountant approval.

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3 years ago

Read 2 more answers

Determine the molar mass of CuSO4 (the solute) in a 1.0M aqueous solution of CuSO4

inna [77]

Answer:

See explanation.

Explanation:

Hello,

In this case, we could have two possible solutions:

A) If you are asking for the molar mass, you should use the atomic mass of each element forming the compound, that is copper, sulfur and four times oxygen, so you can compute it as shown below:

$M_{CuSO_4}=m_{Cu}+m_{S}+4*m_{O}=63.546 g/mol+32.00g/mol+4*16.00g/mol\\\\M_{CuSO_4}=159.546g/mol$

That is the mass of copper (II) sulfate contained in 1 mol of substance.

B) On the other hand, if you need to compute the moles, forming a 1.0-M solution of copper (II) sulfate, you need the volume of the solution in litres as an additional data considering the formula of molarity:

$M=\frac{n_{solute}}{V_{solution}}$

So you can solve for the moles of the solute:

$n_{solute}=M*V_{solution}$

Nonetheless, we do not know the volume of the solution, so the moles of copper (II) sulfate could not be determined. Anyway, for an assumed volume of 1.5 L of solution, we could obtain:

$n_{solute}=1mol/L*1.5L=1.5mol$

But this is just a supposition.

Regards.

4 0

3 years ago

If you have a 550-gram sample of carbon-14 how much remains after 7 half-lives.

Shtirlitz [24]

Idk but you can try to look it up. On google or somewhere else but yea idk about that one

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4 years ago