<span>Pressure will be cut in half
hope that help good luc</span>
This problem is asking for the theoretical effective nuclear charge for sodium and a reason behind its difference with the actual one. At the end, the answers are 1+ and because the 3s¹ electron has a small probability of being closer to the nucleus.
<h3>Effective nuclear charges</h3>
In chemistry, the effective nuclear charge is defined as the net positive charge valence electrons experience. In addition, one can approximate it with the equation:
Zeff = Z – S
Where Z is the atomic number or number of electrons and S the core electrons.
In such a way, since sodium has 11 electrons and 10 core electrons due to its electron configuration (1s²2s²2p⁶3s¹), one concludes its effective nuclear charge is:
Zeff = 11 - 10 = +1
On the other hand, since the actual effective nuclear charge has a value of about 2.667, one concludes this difference is due to the fact that the 3s¹ electron has a small tendency of being closer to the nucleus and therefore, there is a likelihood that this electron undergoes a greater attraction in comparison to the proposed in the theoretical model.
Learn more about effective nuclear charges: brainly.com/question/6965287
Answer:
magnesium has a greater effective nuclear charge than sodium.
Explanation:
Yea but its not used very often
Explanation:
The pH of a solution can you be found by using the formula
![pH = - log [ { H_3O}^{+}]](https://tex.z-dn.net/?f=pH%20%3D%20-%20log%20%5B%20%7B%20H_3O%7D%5E%7B%2B%7D%5D)
Since we are finding the [H3O+] , substitute the value of the pH and find it's antilog
We have
![4.63 = - log[ { H_3O}^{+}] \\ [ { H_3O}^{+}] = {10}^{ - 4.63} \\ \\ = 2.344 \times {10}^{ - 5} mol {dm}^{ - 3}](https://tex.z-dn.net/?f=4.63%20%3D%20%20-%20%20log%5B%20%7B%20H_3O%7D%5E%7B%2B%7D%5D%20%5C%5C%20%5B%20%7B%20H_3O%7D%5E%7B%2B%7D%5D%20%20%20%3D%20%20%7B10%7D%5E%7B%20-%204.63%7D%20%20%5C%5C%20%20%20%5C%5C%20%20%3D%202.344%20%5Ctimes%20%20%7B10%7D%5E%7B%20-%205%7D%20mol%20%7Bdm%7D%5E%7B%20-%203%7D%20%20)
Hope this helps you