I could only find 7!
- independent variable
- dependent variable
- control group
- experimental group
- constant
- observation
- inference
Answer:
It depends what other values you have. Can you give more info? If they give density then you can solve for m.
Answer:
4.1x10⁻⁵
Explanation:
The dissociation of an acid is a reversible reaction, and, because of that, it has an equilibrium constant, Ka. For a generic acid (HA), the dissociation happens by:
HA ⇄ H⁺ + A⁻
So, if x moles of the acid dissociates, x moles of H⁺ and x moles of A⁻ is formed. the percent of dissociation of the acid is:
% = (dissociated/total)*100%
4.4% = (x/[HA])*100%
But x = [A⁻], so:
[A⁻]/[HA] = 0.044
The pH of the acid can be calcualted by the Handersson-Halsebach equation:
pH = pKa + log[A⁻]/[HA]
3.03 = pKa + log 0.044
pKa = 3.03 - log 0.044
pKa = 4.39
pKa = -logKa
logKa = -pKa
Ka = 
Ka = 
Ka = 4.1x10⁻⁵
Nuclear chemist is most concerned with the study of radioactive isotopes.
<h3>What is radioactive isotopes?</h3>
- A chemical element in an unstable state that emits radiation as it decomposes and becomes more stable.
- Radioisotopes can be created in a lab or in the natural world. They are utilized in imaging studies and therapy in medicine. likewise known as radionuclide.
- For instance, soil and rocks contain naturally occurring radioactive isotopes of the elements Radium, Thorium, and Uranium.
- Water also contains trace levels of uranium and thorium. Air contains radon, which is a byproduct of radium's radioactive disintegration.
- There are 254 stable isotopes, although there are more than 3,000 radioisotopes, only roughly 84 of which are found in nature.
Learn more about radioisotopes here:
brainly.com/question/13076859
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<h3>
Answer:</h3>
43.33 atm
<h3>
Explanation:</h3>
We are given;
Mass of C₆H₆ = 26.2 g
Volume of the container = 0.25 L
Temperature = 395 K
We are required to calculate the pressure inside the container;
First, we calculate the number of moles of C₆H₆
Molar mass of C₆H₆ = 78.1118 g/mol.
But; Moles = mass ÷ Molar mass
Moles of C₆H₆ = 26.2 g ÷ 78.1118 g/mol.
= 0.335 moles C₆H₆
Second, we calculate the pressure, using the ideal gas equation;
Using the ideal gas equation, PV = nRT , Where R is the ideal gas constant, 0.082057 L.atm/mol.K
Therefore;
P = nRT ÷ V
= (0.335 mol × 0.082057 × 395 K) ÷ 0.25 L
= 43.433 atm
Therefore, the pressure inside the container is 43.33 atm
