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lawyer [7]
3 years ago
5

Using the following thermochemical equation, calculate how much heat is associated with the decomposition of 4.00 moles of NH4Cl

.
NH3(g) + HCl(g) è NH4Cl(s) ΔH = -176 kJ

A) 5000
B) 740
C) 407
D) 704
Chemistry
2 answers:
andreev551 [17]3 years ago
4 0

Answer:

D

Explanation:

4 \times  - 176 =  - 704

mihalych1998 [28]3 years ago
3 0

Answer:

D - 704

Explanation:

The balanced thermochemical equation relates the energy change to moles, not grams, so we first convert the amount of NH4Ck to moles and then use the thermochemical equation to determine the energy change:

4.00 mole NH4Cl x (-176 ÷ 1 mole NH4Cl)

= -704

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From this, we find that the relation between HNO3 and Ca(OH)2 is that 2 moles of HNO3 react with 1 mole of Ca(OH)2.

2nd) This is the order of the relations that we have to use in the equation to calculate the grams of nitric acid:

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4.30g\text{ Ca\lparen OH\rparen}_2*\frac{1\text{ mol Ca\lparen OH\rparen}_2}{74g\text{ Ca\lparen OH\rparen}_2}*\frac{2\text{ moles HNO}_3}{1\text{ mole Ca\lparen OH\rparen}_2}*\frac{63.02g\text{ HNO}_3}{1\text{ mole HNO}_3}=7.32g\text{ HNO}_3

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Explanation:

oh and also nice profile pic :P

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