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lawyer [7]
3 years ago
5

Using the following thermochemical equation, calculate how much heat is associated with the decomposition of 4.00 moles of NH4Cl

.
NH3(g) + HCl(g) è NH4Cl(s) ΔH = -176 kJ

A) 5000
B) 740
C) 407
D) 704
Chemistry
2 answers:
andreev551 [17]3 years ago
4 0

Answer:

D

Explanation:

4 \times  - 176 =  - 704

mihalych1998 [28]3 years ago
3 0

Answer:

D - 704

Explanation:

The balanced thermochemical equation relates the energy change to moles, not grams, so we first convert the amount of NH4Ck to moles and then use the thermochemical equation to determine the energy change:

4.00 mole NH4Cl x (-176 ÷ 1 mole NH4Cl)

= -704

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What element has a total of 3 p-sublevel electrons?
den301095 [7]

Elements with three p-electrons....


That would be N, P, As, Sb, and Bi -- elements in group 15


For example, energy diagram showing "empty" orbitals up through the 3p.

.....3p __ __ __

3s __

.....2p __ __ __

2s __

1s __


Energy diagram of phosphorous showing three unpaired electrons in 3p-sublevel

.....3p ↑_ ↑_ ↑_

3s ↑↓

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2s ↑↓

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According to Hund's rule, the electrons singly occupy the p-orbitals, and all have the same spin.

8 0
3 years ago
Air enters a diffuser witha velocity of 400 m/s, a pressure of 1 bar and temperature of 25 C. It exits with a temperature of 100
ANEK [815]

Answer:

Exit velocity of air is 96.43 m/s.

Explanation:

Given that

V_1=400\ m/s

T_1=25C

T_2=100C

For air

C_p=1.005\ KJ/kg.K

Now from first law of thermodynamics for open system at steady state

h_1+\dfrac{V_1^2}{2000}+Q=h_2+\dfrac{V_2^2}{2000}+w

For diffuser

h_1+\dfrac{V_1^2}{2000}=h_2+\dfrac{V_2^2}{2000}

We know that

h=C_pT

h_1+\dfrac{V_1^2}{2}=h_2+\dfrac{V_2^2}{2000}

1.005\times 25+\dfrac{400^2}{2000}=1.005\times 100+\dfrac{V_2^2}{2}

V_2=96.43\ m/s

So the exit velocity of air is 96.43 m/s.

8 0
4 years ago
17 Two substances in a mixture differ in density and particle size. These properties can be used to(1) separate the substances
belka [17]
If they're different sizes and densities, you are able to separate the substances. 
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4 years ago
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maksim [4K]

Lithium has charge of +1 and bromide has charge of - 1. So they combine to form the compound lithium bromide which is expressed as LiBr.

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Lithium is the cation and bromide is the anion. So lithium is written in front and bromine following the cation. And as both of their valencies are 1, so they form the compound LiBr.

3 0
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IrinaK [193]
Easy, that's liquid sir.
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