To answer this question, you need to know the aluminum acetate weight and formula. Molecular weight of aluminum acetate is 204.11g/mol, so the concentration should be: (25.20/204.11 )/(0.185l) = 0.1234 mol/0.185l= 0.6673 M<span>
</span>The aluminum acetate Al(C2H3O2)3 which mean for one aluminum acetate there will be 3 acetate ion. The concentration of acetate should be: 0.6673 M= 2M
There will be 1.11 grams of the sample of radon-222 left. This answer can be obtained using the formula of half life to get the rate constant which will be used in another equation later on.
Half-life (t) = ln2/k = 3.8 days
k = 0.182407/day
Using the general equation of a first order reaction:
Ca/Cao = 1/e^(kt)
Ca/Cao = 0.01506 --> fraction of radon-222 left
This means that 1.51% of the original amount remains, so 1.51% of 73.9 is 1.11 grams.
Ice, water, fog/water vapor