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zhenek [66]
3 years ago
7

What is the pH of a 0.50 M C6H5NH3Br solution? KbC6H5NH2 = 3.9x10-10 (R = 2.45)

Chemistry
1 answer:
masya89 [10]3 years ago
3 0

Answer:

It commonly ranges between 0 and 14, but can go beyond these values if sufficiently acidic/basic. pH is logarithmically and inversely related to the concentration of hydrogen ions in a solution. The pH to H + formula that represents this relation is: The solution is acidic if its pH is less than 7.

Explanation:

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Using the equation 40kJ+2SO3(g)-->2SO2(g) + O2(g), if pressure is added what way
Ad libitum [116K]

In an equation, 40kJ + 2SO₃ (g) -->2SO₂(g) + O₂(g), if pressure added, the equilibrium shifts to the left side of the reaction because it has fewer moles of gas.

<h3>What is Le Ch atelier's principle?</h3>

Le Ch atelier's principle states that if the pressure is added in a nay reaction, then the equilibrium will be shifted toward the side where there are fewer atoms.

In this case, there are fewer moles on the left side.

Thus, when pressure is added, the equilibrium shift to the left side due to Le Ch atelier's principle.

Learn more about Le Ch atelier's principle

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6 0
2 years ago
What will be the volume of a gas sample at 337 K if its volume at 237 K is 12.0 L? Round your answer to 1 digit after the decima
oksano4ka [1.4K]

Answer:

17.1 L

Explanation:

V1/T1=V2/T2

V2=(V1*T2)/T1

V2= (12.0L * 337K)/237K

V2=17.1L

7 0
4 years ago
Help please!
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I think that the empirical formula is mgcl2

3 0
3 years ago
"would you expect to find sodium chloride in underground rock deposits as a solid, liquid, or gas? explain."
Sophie [7]

A sodium chloride is like most of the ionic compounds existing here on earth in which they are composed of having a high melting point and by this, if found in underground rock deposits, they are usually in a form of solid.

3 0
3 years ago
A 275-mL flask contains pure helium at a pressure of 752 torr. A second flask with a volume of 475 mL contains pure argon at a p
hichkok12 [17]

Answer:

  • Partial pressure He = 276 torr
  • Partial pressure Ar = 457 torr
  • Total pressure = 733 torr

Explanation:

Assuming temperature remains constant, we can use Boyle's law to solve this problem: P₁V₁=P₂V₂.

Once the two flasks are connected and the stopock opened, the total volume is:

  • 275 + 475 = 750 mL

Now we use Boyle's law <em>twice</em>, to <u>calculate the new pressure of </u><em><u>each</u></em><u> gas</u>:

  • He ⇒ 752 torr * 275 mL = P₂He * 750 mL

P₂He = 276 torr

  • Ar ⇒ 722 torr * 475 mL = P₂Ar * 750 mL

P₂Ar = 457 torr

Finally we <u>calculate the total pressure</u>, adding the partial pressures:

  • Total pressure = P₂He + P₂Ar = 733 torr
4 0
3 years ago
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