2(x - 5) = 110
2x - 10 = 110
Add 10 to both sides.
2x = 120
Divide by 2 on both sides.
x = 60
Answer: Last Option
Step-by-step explanation:
The initial height of the plant of species A is 25 cm and grows 3 centimeters per month.
If m represents the number of months elapsed then the equation for the height of the plant of species A is:
For species B the initial height is 10 cm and it grows 8 cm each month
If m represents the number of months elapsed then the equation for the height of the plant of species B is:
Finally, the system of equations is:
The answer is the last option
Answer:
The correct answer is 149.00.
Step-by-step explanation:
Part = Percent • Whole
Adding a 65% markup to the original price of 105 is simply multiplying the price by the decimal form of the markup, then adding that to the original price. Next, you would find 20% of your sum by multiplying the sum by 0.20. Then you would find 7.5% of <em>that</em> and add this to the price.
Solve:
105 • 0.65 = 68.25 Find 65% of 105
105 + 68.25 = 173.25 Add the markup to the price
173.25 • 0.20 = 34.65 Find the discount of the new price
173.25 - 34.65 = 138.60 Subtract discount from price
138.60 • 0.075 = 10.395 Find sales tax of new price (Or round to 10.40)
<u>138.60 + 10.395 = </u><u>148.995</u><u> Add sales tax to new price (Or </u><u>149</u><u>)</u>
Because money only goes to the hundredths place, we can either start rounding to that place in the second to last step - rounding 10.395 to 10.40 - or we can round our answer - 148.995 rounds to 149. Either way, we will still get an answer of $149.00.
Hope this helps.
♥<em>A.W.E.</em><u><em>S.W.A.N.</em></u>♥
<span>Often the university sites exist primarily for internal use, listing equipment and demos available to physics professors teaching large sections of introductory courses. They usually give lists of required equipment, they don't always give much information about setup, effective presentation and explanation of the physics.</span>
Pretty sure it's A ?? That's what I got. I'm taking this right now.
