3 years ago

Magnitude of an earthquake M = log1

Mathematics

1 answer:

belka [17]3 years ago

6 0

M = 4
Because the base of log is 10
10,000 is 10*4, and we know that log 10,000 =4, so M=4

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Yanka [14]

Answer:

The last option

Step-by-step explanation:

The last option

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3 years ago

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Expand the given power using the Binomial Theorem. (10k – m)5

agasfer [191]

Answer:

$(10k - m)^{5}=100000k-50000k^{4}m+10000k^{3}m^{2}-1000k^{2}m^{3}+50km^{4}-m^{5}$

Step-by-step explanation:

* Lets explain how to solve the problem

- The rule of expand the binomial is:

$(a+b)^{n}=(a)^{n}+nC1(a)^{n-1}(b)+nC2(a)^{n-2}(b)^{2}+nC3(a)^{n-3}(b)^{3}+...............+(b)^{5}$

∵ The binomial is $(10k-m)^{5}$

∴ a = 10k , b = -m and n = 5

∴ $(10k-m)^{5}=(10k)^{5}+5C1(10k)^{4}(-m)+5C2(10k)^{3}(-m)^{2}+5C3(10k)^{2}(-m)^{3}+5C4(10k)^{1} (-m)^{4}+5C5(10k)^{0}(-m)^{5}$

∵ 5C1 = 5

∵ 5C2 = 10

∵ 5C3 = 10

∵ 5C4 = 5

∵ 5C5 = 1

∴ $(10k-m)^{5}=100000k^{5}+(5)(10000)k^{4}(-m)+(10)(1000)k^{3}(m^{2})+(10)(100)k^{2}(-m^{3})+5(10k)^{1} (m^{4})+(10k)^{0}(-m^{5})$

∴ $(10k-m)^{5}=100000k^{5}-50000)k^{4}m+10000k^{3}m^{2}-1000k^{2}m^{3}+50km^{4}-m^{5}$

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3 years ago

the diagonal of a rectangle is 16 inches. if the height of the rectangle is 8 inches. what is the length of the rectangle?

Yakvenalex [24]

Answer:

Length: 13.9 inches

Step-by-step explanation:

a^2 + b^2 = c^2

a = 8 and c= 16

8^2 + b^2 = 16^2

64 + b^2 = 256

b^2 = 256 - 64

b = sqrt 192

b = 13.9

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3 years ago

Y=6 x=5 <br><br>xy+7-y<br><br>please help mee

Afina-wow [57]

5•6+7-6
30+7-6
37-6
=31

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3 years ago

what is the probability that the box of pizza you just bought will be the grand prize winner when out the next 100,000 boxes ran

Olenka [21]

That means one box out of 100,000 boxes will have a chance of winning.
That means 1/100,000.
0.00001 or 0.001%

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4 years ago