Answer:
y = -3
Step-by-step explanation:
Parallel to the x axis means that it is a horizontal line
It is of the form y =
Given the point ( 5, -3)
The y value is -3
y = -3
Answer:
20*30km = 600km
15*30km = 450km
600km * 450km = 270000 km^2
Step-by-step explanation:
assuming 1cm --- 30km causes that 2cm --- 60km, 3cm --- 90km, 4cm --- 120km etc. Notice that number of km's is 30 times greater than the number of cm's on a map
using this logic, you calculate both real dimensions of Colorado by multiplying 20*30 = 600 km and 15*30 = 450km
Then we use a formula of an area of a rectangle 
assuming 
and get 
which is an actual area of Colorado
Answer:
Option 4. 256 - 64π is the correct option.
Step-by-step explanation:
In the given picture a square is circumscribed about a circle with a side = 2r
where r is the radius of the circle.
Therefore area of the square = (2r)² = 4r² = 4 × 8² = 4 × 64 = 256 in²
Now area of the circle = πr² = π × 8² = 64π in²
Now area of region that is inside the square and outside the circle =
Area of square - area of circle = (256 - 64π) in².
Therefore the answer is (256 - 64π).
Answer:
what is the area of triangle ABC choices
35 square unit
Answer:
The parenthesis need to be kept intact while applying the DeMorgan's theorem on the original equation to find the compliment because otherwise it will introduce an error in the answer.
Step-by-step explanation:
According to DeMorgan's Theorem:
(W.X + Y.Z)'
(W.X)' . (Y.Z)'
(W'+X') . (Y' + Z')
Note that it is important to keep the parenthesis intact while applying the DeMorgan's theorem.
For the original function:
(W . X + Y . Z)'
= (1 . 1 + 1 . 0)
= (1 + 0) = 1
For the compliment:
(W' + X') . (Y' + Z')
=(1' + 1') . (1' + 0')
=(0 + 0) . (0 + 1)
=0 . 1 = 0
Both functions are not 1 for the same input if we solve while keeping the parenthesis intact because that allows us to solve the operation inside the parenthesis first and then move on to the operator outside it.
Without the parenthesis the compliment equation looks like this:
W' + X' . Y' + Z'
1' + 1' . 1' + 0'
0 + 0 . 0 + 1
Here, the 'AND' operation will be considered first before the 'OR', resulting in 1 as the final answer.
Therefore, it is important to keep the parenthesis intact while applying DeMorgan's Theorem on the original equation or else it would produce an erroneous result.
