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labwork [276]
3 years ago
15

Find the difference: -3/5 - (-5/9)

Mathematics
2 answers:
Stella [2.4K]3 years ago
6 0

Answer:

-2/45

Step-by-step explanation:

-3/5 - (-5/9)

Subtracting a negative is like adding

-3/5 + 5/9

Get a common denominator of 45

-3/5*9/9    + 5/9 *5/5

-27/45 + 25/45

-2/45

stepladder [879]3 years ago
6 0

<em>Greetings from Brasil... </em>

(-3/5) - (-5/9)

(-3/5) + (5/9)

<em>MMC 45</em>

-27/45 + 25/45

<h2>- 2/45</h2>

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Select all the points that are on the line through (0 5) and (2 8) A.(5 11) B.(5 10) C.(6 14) D.(30 50) E.(40 60)
mihalych1998 [28]

Answer:

Options C. and D. are correct.

Step-by-step explanation:

Let (x_1,y_1)=(0,5),\,(x_2,y_2)=(2,8)

Equation of a line is given by y-y_1=(\frac{y_2-y_1}{x_2-x_1})(x-x_1)

y-5=(\frac{8-5}{2-0})(x-0)\\\\y-5=\frac{3}{2}x\\\\2y-10=3x\\3x-2y+10=0

Put  (x,y)=(5,11)

3(5)-2(11)+10=15-22+10=3\neq 0

Put  (x,y)=(5,10)

3(5)-2(10)+10=15-20+10=5\neq 0

Put (x,y)=(6,14)

3(6)-2(14)+10=18-28+10=0

Put (x,y)=(30,50)

3(30)-2(50)+10=90-100+10=0

Put (x,y)=(40,60)

3(40)-2(60)+10=0\\120-120+10=10\neq 0

So, points (6,14),\,(30,50) satisfy the equation 3x-2y+10=0

Therefore,

points (6,14),\,(30,50) lie on the line through (0,5) and (2,8)

Options C. and D. are correct.

8 0
3 years ago
The reading of a scale at one end is 3.5 cm and at the other end is 18.5 cm. Calculate the lengths of the needle
Bumek [7]

Answer:

15 cm

Step-by-step explanation:

Given that :

Reading at one end, initial reading = 3.5 cm

Reading at the other end, final reading = 18.5 cm

Length of needle :

Final Reading - Initial reading

18.5cm - 3.5cm

= 15cm

6 0
3 years ago
If a right triangle has two legs a=7 and b=4, what is the length of the hypotenuse
DENIUS [597]
A^2 + b^2 = c^2
7^2 + 4^2 = 65
square root of 65 is 8.06
answer: 8.06
5 0
3 years ago
I need help with part b. I feel like there’s a catch, I want to do the first derivative test, however, I feel like there is a be
Sladkaya [172]

Answer:

The fifth degree Taylor polynomial of g(x) is increasing around x=-1

Step-by-step explanation:

Yes, you can do the derivative of the fifth degree Taylor polynomial, but notice that its derivative evaluated at x =-1 will give zero for all its terms except for the one of first order, so the calculation becomes simple:

P_5(x)=g(-1)+g'(-1)\,(x+1)+g"(-1)\, \frac{(x+1)^2}{2!} +g^{(3)}(-1)\, \frac{(x+1)^3}{3!} + g^{(4)}(-1)\, \frac{(x+1)^4}{4!} +g^{(5)}(-1)\, \frac{(x+1)^5}{5!}

and when you do its derivative:

1) the constant term renders zero,

2) the following term (term of order 1, the linear term) renders: g'(-1)\,(1) since the derivative of (x+1) is one,

3) all other terms will keep at least one factor (x+1) in their derivative, and this evaluated at x = -1 will render zero

Therefore, the only term that would give you something different from zero once evaluated at x = -1 is the derivative of that linear term. and that only non-zero term is: g'(-1)= 7 as per the information given. Therefore, the function has derivative larger than zero, then it is increasing in the vicinity of x = -1

6 0
3 years ago
**The following scenario is for #12, #13, and #14 on this test.** A school chorus has 90 sixth grade students and 75 seventh gra
givi [52]

Answer:

The music director can make 15 groups of performers with 6 sixth grade students and 5 seventh grade students in each group.

Step-by-step explanation:

A school chorus has 90 sixth-grade students and 75 seventh-grade students.

Factor these two numbers:

Find GCF(90,75):

Now,

Therefore, the music director can make 15 groups of performers with 6 sixth grade students and 5 seventh grade students in each group.

6 0
2 years ago
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