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mariarad [96]
3 years ago
7

0.58 divided by 0.5568

Mathematics
1 answer:
vivado [14]3 years ago
6 0

Answer:

1.04166666667

Step-by-step explanation:

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Finding an Equation of a Tangent Line In Exercise, use implicit differentiation to find an equation of the tangent line to the g
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Equation of tangent line at point (1,0) to given function is

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Step-by-step explanation:

Equation of tangent line is

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where m is slope of line and can be found by implicitly differentiating the given function w.r.to x

x+y-1=ln(x^{2}+y^{2})\\\\\frac{d}{dx}(x+y-1)=\frac{d}{dx}(ln(x^{2}+y^{2})\\\\1+\frac{dy}{dx}=\frac{2x}{x^{2}+y^{2}}+\frac{2y}{x^{2}+y^{2}}\frac{dy}{dx}\\\\\frac{dy}{dx}=\frac{2x-x^{2}-y^{2}}{x^{2}+y^{2}-2y}\\\\at \,(1,0)\\\\\frac{dy}{dx}=\frac{2(1)-1-0}{1+0-0}\\\\\frac{dy}{dx}=1\\\\

which is slope of tangent line. At (1,0) equation of tangent line is

                            y-0=1(x-1)\\\\y=x-1

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4 years ago
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