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sergiy2304 [10]
3 years ago
6

Please hurry I'm due tmr hurry and thanksss ​

Mathematics
2 answers:
Nutka1998 [239]3 years ago
8 0

Answer:

2) -2/3

4) 17/5

Step-by-step explanation:

2)-4/3= 2g

-4=6g

g=-2/3

4) 9=5r - 8

-5r=-17

r=17/5

vitfil [10]3 years ago
3 0

Answer:

g=-2/3, r=17/5, -15/14

Step-by-step explanation:

Multiply all terms by the same value to eliminate fraction denominators

<u><em>2) </em></u>-4/3=g/1/2

1/2(-4/3)= 1/2xg/1/2

Simplify

<em>Multiply the numbers:</em>

1/2(-4/3)=1/2xg/1/2

-2/3= 1/2xg/1/2

<em>Cancel multiplied terms that are in the denominator</em>

-2/3= 1/2xg/1/2 (cross out 1/2)

-2/3= g

<em>Move the variable to the left</em>

-2/3=g

g=-2/3

4)

<em>Multiply the numbers</em>

9/5=r-1x8.5

9/5=r-8/5

<em>Add 8/5 to both sides of the equation</em>

9/5=r-8/5

9/5+8/5=r-8/5+8/5

<em>Add the numbers:</em>

9/5+8/5=r-8/5+8/5

17/5=r

<em>Move the variables to the left</em>

17/5=r

r=17/5

6)

4/5z=-6/7

divide 4/5 5o each side

4/5zx5/4=-6/7x5/4

z=-30/28

(simplified= -15/14)

Your welcome ^^

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Step-by-step explanation:

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7 0
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Read 2 more answers
Please help!
crimeas [40]

Answer:

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  • The function has three distinct real zeros.

Hence, option (B) is true.

Step-by-step explanation:

Given the expression

h\left(x\right)=\left(x-4\right)^2\left(x^2-7x+\:10\right)

Let us determine the zeros of the function by putting h(x) = 0 and solving the expression

0=\left(x-4\right)^2\left(x^2-7x+10\right)

switch sides

\left(x-4\right)^2\left(x^2-7x+10\right)=0

as

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\left(x-4\right)^2\left(x-2\right)\left(x-5\right)=0

Using the zero factor principle

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so

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