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Licemer1 [7]
4 years ago
9

a 5.0 gallon container contains 15.0 moles of propane gas at room temperature (20. °c). what is the pressure of the gas? (1.0 ga

l = 3.79 l)
Chemistry
1 answer:
gayaneshka [121]4 years ago
4 0
We apply the ideal gas equation:
PV = nRT
V = 5 x 3.79/1000 m³
= 0.01895
T = 20 + 273 = 293 K
n = 15
R = 8.314
P = nRT/V
= (15 x 8.314 x 293)/(0.01895)
= 1,928,234 Pa ≈ 1.93 MPa
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4 Na + O2 2 Na20 grams of Na are required to produce 52.45 grams of Na2O. Round your answer to the nearest whole number​
lukranit [14]

Answer:

4

N

a

+

O

2

→

2

N

a

2

O

.

By the stoichiometry of this reaction if 5 mol natrium react, then 2.5 mol

N

a

2

O

should result.

Explanation:

The molecular mass of natrium oxide is

61.98

g

⋅

m

o

l

−

1

. If

5

m

o

l

natrium react, then

5

2

m

o

l

×

61.98

g

⋅

m

o

l

−

1

=

154.95

g

natrium oxide should result.

So what have I done here? First, I had a balanced chemical equation (this is the important step; is it balanced?). Then I used the stoichiometry to get the molar quantity of product, and converted this molar quantity to mass. If this is not clear, I am willing to have another go.

Explanation:

5 0
3 years ago
Q1.What is the mass of 5 moles Of 1.Mg 2.CaCO3 Q2. Calculate the number of atoms in 10g of Na Q3.calculate the number of molecul
Phoenix [80]

Answer:

Explanation:

Q1) as we know that moles=given mass/molar mass

     mass of 5 moles of Mg is

mass =moles*molar mass

mass=5*24

mass=120 g

mass of 5 moles of CaCO3 is

mass= moles*molar mass

mass=5*100=500

Q2) number of atoms in 10 g Na

first we need number of moles of sodium

moles =mass/molar mass

moles=10/23=0.43

now we know that moles=number of atoms /avogadro number

for number of atom the formula become

number of atom=moles*avogadro number

number of atom=0.43*6.023*10^23=2.6*10^23

Q3)number of molecule in 10 g of NaCl

again we need number of moles of NaCl

moles=given mass/molar mass

moles=10/58.5=0.17

now number of molecules=moles*avogadro number

number of molecules=0.17*6.023*10^23=1.02*10^23

Q4) avogadro number is the number of particles(atoms,molecules,ions) present in one mole of a substance its value is 6.023*10^23

Q5)Number of atoms in 4g of oxygen

again we need number of moles of oxygen

moles=mass/molar mass

moles=4/16=0.25

now number of atoms=moles*avogadro number

number of atoms=0.25*6.023*10^23 =1.5*10^23

3 0
3 years ago
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Answer:

Please find equations in the attachment file.  

Explanation:

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