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amid [387]
3 years ago
5

How does cooler air move in relation to warmer air?

Chemistry
1 answer:
ladessa [460]3 years ago
7 0
Answer:
Cool air moves down while hot air rises
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Which equation correctly shows an endothermic reaction? *
Nady [450]
It’s A because +1500 kJ is before the arrow. it’s in the reactant side. so it is endothermic.
8 0
3 years ago
What is the primary source of energy for hydrothermal vent communities?
Novay_Z [31]
C. oxidation of<span> hydrogen sulfide from the vent water
is the answer.</span>
3 0
3 years ago
How do mass and type of material affect thermal energy transfer?
Lerok [7]

Answer:

Temperature, mass, and the type of material are factors that affect the thermal energy of an object.

Material with the higher specific heat will have more thermal energy than material with lower specific heat if they both have the same mass and temperature.

3 0
3 years ago
One way in which the useful metal copper is produced is by dissolving the mineral azurite, which contains copper (II) carbonate,
bekas [8.4K]

Answer:

6,04x10⁻³M

Explanation:

For the reaction:

Fe(s) + CuSO₄(aq) → Cu(s) + FeSO₄(aq)

The precipitate of Cu(s) weights 96,0 mg. In moles:

Moles of Cu(s):

0,096g×(1mol/63,546g) = 1,51x10⁻³ moles of Cu(s). If you see the balanced equation 1 mole of CuSO₄ produce 1 mole of Cu(s). That means moles of CuSO₄ are the same of Cu(s), <em>1,51x10⁻³ moles of CuSO₄</em>

As volume of the solution is 250 mL, 0,250L, the molar concentration of the original solution is:

1,51x10⁻³ moles of CuSO₄ / 0,250L = <em>6,04x10⁻³M</em>

I hope it helps!

8 0
4 years ago
A tire is filled to a gauge pressure of 2 atm at 27 degrees Celsius after a drive the temperature within the tire rises to 47 de
Ivenika [448]

Answer:

2.13atm

Explanation:

The following information were obtained from the question:

P1 (initial pressure) = 2atm

T1 (initial temperature) = 27°C = 27 + 273 = 300K

T2 (final temperature) = 47°C = 47 + 273 = 320K

P2 (final pressure) =?

Using the equation P1/T1 = P2/T2, the final pressure within the tyre can be obtained as illustrated below:

P1/T1 = P2/T2

2/300 = P2/320

Cross multiply to express in linear form

300 x P2 = 2 x 320

Divide both side by 300

P2 = (2 x 320)/300

P2 = 2.13atm

Therefore, the pressure within the tyre at 47°C is 2.13atm

4 0
3 years ago
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