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Pie
3 years ago
15

the volume of a large can of tuna fish can be calculated by using the formula V= *pi*r^2h. write an equation to find the radius,

r, in terms of V and h
Mathematics
2 answers:
Dmitry_Shevchenko [17]3 years ago
5 0
V=\pi r^2h\\
r^2=\dfrac{V}{\pi h}\\
r=\sqrt{\dfrac{V}{\pi h}

Svet_ta [14]3 years ago
4 0
V= pi x r^2 x h

V/(pi x h)=r^2

square root of [V/(pixh)]=r
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3 years ago
Use partial quotients to solve 504 divide 14
miv72 [106K]

Answer:

Perform the following division using partial quotients: 504 ÷ 14:

To reduce the numerator, we will be multiplying the denominator by factors of 10, 5, 2, and 1

Step-by-step explanation:

1 4| 5 0 4

2 8 0 20 <---- 20 x 14 = 280

2 2 4 <---- 504 - 280 = 224

1 4| 5 0 4

2 8 0 20

2 2 4

1 4 0 10 <---- 10 x 14 = 140

8 4 <---- 224 - 140 = 84

1 4| 5 0 4

2 8 0 20

2 2 4

1 4 0 10

8 4

7 0 5 <---- 5 x 14 = 70

1 4 <---- 84 - 70 = 14

1 4| 5 0 4

2 8 0 20

2 2 4

1 4 0 10

8 4

7 0 5

1 4

1 4 1 <---- 1 x 14 = 14

0 <---- 14 - 14 = 0

Our partial quotients add up as follows:

20 + 10 + 5 + 1 = 36

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5 0
3 years ago
Consider the following relation.
Jet001 [13]

Answer:

(0,-1),(1,0),(2,1),(3,2)

Step-by-step explanation:

We are given that a relation

y=x+1y=x+1

We have to find the four points contained in the inverse

The given function is linear function

Therefore,

Domain of function=R

Range of function=R

x=y-1x=y−1

Now, replace x by y and y replace by x

y=x-1y=x−1

Now, substitute y=f^{-1}(x)=f

−1

(x)

f^{-1}(x)=x-1f

−1

(x)=x−1

It is linear function and defined for all real values.

Substitute x=0

f^{-1}(0)=-1f

−1

(0)=−1

Substitute x=1

f^{-1}(1)=1-1=0f

−1

(1)=1−1=0

f^{-1}(2)=2-1=1f

−1

(2)=2−1=1

f^{-1}(3)=3-1=2f

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(3)=3−1=2

Therefore, four points contained in the inverse (0,-1),(1,0),(2,1) and (3,2)

6 0
3 years ago
What is the y-intercept of the line described by the equation y= 7x+4
Eddi Din [679]
The slope-intercept form: y = mx + b

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3 years ago
A company orders 29 boxed lunches from a deli for $324.80. If each boxed lunch
UkoKoshka [18]

Answer:

Each boxed lunch costs $11.20

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