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2 years ago

Helppppppppppppppppppppppp

Mathematics

1 answer:

alukav5142 [94]2 years ago

6 0

The answer is a. Irrationally numbers, when written as decimal numbers do not terminate nor do they repeat

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The length and width of a rectangle are measured as 55 cm and 49 cm, respectively, with an error in measurement of at most 0.1 c

valentina_108 [34]

Answer:

The maximum error in the calculated area of the rectangle is $10.4 \:cm^2$

Step-by-step explanation:

The area of a rectangle with length $L$ and width $W$ is $A= L\cdot W$ so the differential of <em>A</em> is

$dA=\frac{\partial A}{\partial L} \Delta L+\frac{\partial A}{\partial W} \Delta W$

$\frac{\partial A}{\partial L} = W\\\frac{\partial A}{\partial W}=L$ so

$dA=W\Delta L+L \Delta W$

We know that each error is at most 0.1 cm, we have $|\Delta L|\leq 0.1$ , $|\Delta W|\leq 0.1$ . To find the maximum error in the calculated area of the rectangle we take $\Delta L = 0.1$ , $\Delta W = 0.1$ and $L=55$ , $W=49$ . This gives

$dA=49\cdot 0.1+55 \cdot 0.1$

$dA=10.4$

Thus the maximum error in the calculated area of the rectangle is $10.4 \:cm^2$

4 0

2 years ago

Which graph shows a function and it’s inverse? <br><br> HELP PLEASE

TEA [102]

Answer:

Step-by-step explanation:

A function and its inverse are obtained by reflecting in the line y = x

Under a reflection in the line y = x

a point (x, y ) → (y, x )

In graph C

the red line has a point (0, 2 )

the blue line has a point (2, 0 )

Then graph C shows a function and its inverse

8 0

2 years ago

I need help can u help me please and thanks

son4ous [18]

Answer:

17.74

Step-by-step explanation:

The fraction is easily converted to one with a denominator of 100 (a power of 10):

$\dfrac{37}{50}=\dfrac{37\cdot 2}{50\cdot 2}=\dfrac{74}{100}=0.74$

Then the number of interest is ...

17 37/50 = 17 74/100 = 17.74

3 0

2 years ago

This extreme value problem has a solution with both a maximum value and a minimum value. use lagrange multipliers to find the ex

harina [27]

$L(x,y,z,\lambda)=8x+8y+4z+\lambda(4x^2+4y^2+4z^2-36)$

$L_x=8+8\lambda x=0\implies 1+\lambda x=0$
$L_y=8+8\lambda y=0\implies 1+\lambda y=0$
$L_z=4+8\lambda z=0\implies 1+2\lambda z=0$
$L_\lambda=4x^2+4y^2+4z^2-36=0\implies x^2+y^2+z^2=9$

$yL_x=y+\lambda xy=0$
$xL_y=x+\lambda xy=0$
$\implies yL_x-xL_y=y-x=0\implies y=x$

$2zL_x=2z+2\lambda xz=0$
$xL_z=x+2\lambda xz=0$
$\implies 2zL_x-xL_z=2z-x=0\implies x=2z$

$2zL_y=2z+2\lambda yz=0$
$yL_z=y+2\lambda yz=0$
$\implies 2zL_y-yL_z=2z-y=0\implies y=2z$

$x=y=2z\implies x^2+y^2+z^2=9\iff 4z^2+4z^2+z^2=9z^2=9\implies z=\pm1$

$z=\pm1\implies y=x=\pm2$

So we have two critical points, (2, 2, 1) and (-2, -2, -1), which respectively give a max of 36 and a min of -36.

5 0

2 years ago

If f(x)=e^2x(x^3+1) then f'(2)=

qaws [65]

Answer:

See below

Step-by-step explanation:

$f(x)=e^2x(x^3+1) = e^2x^4+x$