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FromTheMoon [43]
3 years ago
12

A $200,000 loan amortized over 12 years at an interest rate of 10% per year requires payments of $21,215.85 to completely remove

the loan when interest is charged on the unrecovered balance of the principal. If interest is charged on the original principal instead of the unrecovered balance, what is the loan balance after 12 years provided the same $21,215.85 payments are made each year?
Business
1 answer:
lesya [120]3 years ago
6 0

Answer:

loan balance after 12 years = $185409.8

Explanation:

Loan principal = $200000

interest = 10% of principal

amount paid yearly  = $21215.85

For 1st year

principal for the first year = $200000

required interest to be paid = 10% of 200000 = $20000

amount paid = $21215.85

Loan Balance after first year = (principal for first year) - (amount paid - 10% of principal ) = $198,784.15

For 2nd year

principal for the 2nd year = Loan balance after first year = $198,784.15

loan balance after 2nd year = 198784.15 - ( 21215.85 - 10% of 198784.15)

= $197568.30

same applies for the different years until the 12th year

using this formula :

Loan Balance after Nth year = [ Loan balance after (n-1) year - ( amount paid - 10% of loan balance after (n-1) year ) ]

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1. What situations might have created the budget deficit for the Constantine family?
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In money terms, what was the opportunity cost of Shawn’s savings decision? What was the benefit? In the worksheet a tale of two
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Let the random variable Z follow a standard normal distribution.
Bas_tet [7]

Answer:

(a) <em>z</em> = 0.53

(b) <em>z</em> -0.67

(c) <em>z</em> = -0.84

(d) <em>z</em> = 0.26

Explanation:

A standard normal distribution has mean 0 and standard deviation 1.

(a)

Compute the value of <em>z</em> for P (<em>Z</em> < <em>z</em>) = 0.70 as follows:

Consider the<em> </em>standard normal table for the value of <em>z.</em>

The value of <em>z</em> is 0.53.

(b)

Compute the value of <em>z</em> for P (<em>Z</em> < <em>z</em>) = 0.25 as follows:

Consider the<em> </em>standard normal table for the value of <em>z.</em>

The value of <em>z</em> is -0.67.

(c)

Compute the value of <em>z</em> for P (<em>Z</em> > <em>z</em>) = 0.20 as follows:

P (Z > z) = 0.20

1 - P (Z < z) = 0.20

P (Z < z) = 0.80

Consider the<em> </em>standard normal table for the value of <em>z.</em>

The value of <em>z</em> is -0.84.

(d)

Compute the value of <em>z</em> for P (<em>Z</em> > <em>z</em>) = 0.60 as follows:

P (Z > z) = 0.60

1 - P (Z < z) = 0.60

P (Z < z) = 0.40

Consider the<em> </em>standard normal table for the value of <em>z.</em>

The value of <em>z</em> is 0.26.

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3 years ago
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